[Wien] problem with supercell
Yaron and Angelica
strutza at bgumail.bgu.ac.il
Fri Jul 18 16:53:24 CEST 2003
Hello Stefaan,
Friday, July 18, 2003, 10:25:15 AM, you wrote:
SC> From what I see above, you have even in the cell without vacancy 16
SC> inequivalent atoms and only 1 symmetry operation ??? For a supercell this cannot be.
Could you refer me to a way of correcting this problem?
SC> Can you construct a unit cell for the small, regular cell?
Yes, I constructed a unit cell - 2 inequivalent atoms, space group
Pm-3m and there was 48 symmetry operations.
After that in a new session I took 16 atoms Fe1,...Fe8, Al1,...Al8;
And the same space group P m-3m.
SC> Did you run sgroup on the large cell?
Yes
SC> Didn't sgroup propose to make some atoms equivalent?
No, sgroup didn't propose.
Commandline: x nn -up -c
Program input is: "2 "
please specify nn-bondlength factor: (usually=2)
NAMED ATOM: Fe1 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe2 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe3 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe4 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe5 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe6 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe7 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Fe8 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al1 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al2 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al3 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al4 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al5 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al6 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al7 Z changed to IATNR+200 to determine equivalency
NAMED ATOM: Al8 Z changed to IATNR+200 to determine equivalency
ATOM 1 Fe1 ATOM14 Al6
RMT( 1)=2.00000 AND RMT(14)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 2 Fe2 ATOM11 Al3
RMT( 2)=2.00000 AND RMT(11)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 3 Fe3 ATOM14 Al6
RMT( 3)=2.00000 AND RMT(14)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 4 Fe4 ATOM15 Al7
RMT( 4)=2.00000 AND RMT(15)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 5 Fe5 ATOM10 Al2
RMT( 5)=2.00000 AND RMT(10)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 6 Fe6 ATOM10 Al2
RMT( 6)=2.00000 AND RMT(10)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 7 Fe7 ATOM10 Al2
RMT( 7)=2.00000 AND RMT(10)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 8 Fe8 ATOM 9 Al1
RMT( 8)=2.00000 AND RMT( 9)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM 9 Al1 ATOM 1 Fe1
RMT( 9)=2.00000 AND RMT( 1)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM10 Al2 ATOM 6 Fe6
RMT(10)=2.00000 AND RMT( 6)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM11 Al3 ATOM 1 Fe1
RMT(11)=2.00000 AND RMT( 1)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM12 Al4 ATOM 4 Fe4
RMT(12)=2.00000 AND RMT( 4)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM13 Al5 ATOM 1 Fe1
RMT(13)=2.00000 AND RMT( 1)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM14 Al6 ATOM 3 Fe3
RMT(14)=2.00000 AND RMT( 3)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM15 Al7 ATOM 4 Fe4
RMT(15)=2.00000 AND RMT( 4)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
ATOM16 Al8 ATOM 4 Fe4
RMT(16)=2.00000 AND RMT( 4)=2.00000
SUMS TO 4.00000 LT. NN-DIST= 6.72623
STOP: NN ENDS
0.0u 0.0s 0:00 0% 0+0k 0+0io 0pf+0w
Im sorry to bother you with my lack of knowladge on this subject as i
am still new to WIEN2k, and i thank you for the help.
--
Best regards,
Angelica mailto:strutza at bgumail.bgu.ac.il
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