[Wien] "x nn" problem

[Jorissen Kevin]

Hello Bing Zhou & Lukasz,
the answer is much more simple.
 
The "5" in "atom 5" corresponds to the number of an inequivalent atom class in case.struct.  Apparently, this class contains more than one atom in the unit cell, either because there is more than one entry for atom 5 in case.struct, or your lattice type (e.g. F) generates more positions.
Nn verifies that NO atoms in the unit cell overlap, whether they belong to the same equivalency class or not.  In your case, the distance between two different atom positions both belonging to equivalency class 5 was calculated.
 
So there is nothing strange about this.
 
1 a.u. is a rather small nearest neighbour distance, maybe you did input the lattice constants in A instead of a.u., as Lukasz suggested?
 
Kevin.
 
PS Lukasz, in fact, if you go to case.outputnn, you can find out exactly which atom positions correspond to a particular interatomic distance - nn tends to write endless lists of those.

	-----Oorspronkelijk bericht----- 
	Van: Lukasz Plucinski [mailto:pluto at buphy.bu.edu] 
	Verzonden: za 10/11/2003 1:35 
	Aan: wien at zeus.theochem.tuwien.ac.at 
	CC: 
	Onderwerp: Re: [Wien] "x nn" problem
	
	

	> Why did my "init_lapw" give the distance between atom 5 and atom 5?
	>
	>
	>    ERROR !!!!!!!!!!!!!!!
	>  RMT(  5)=0.70000 AND RMT(  5)=0.70000
	>  SUMS TO 1.40000 GT NNN-DIST= 1.05157
	
	Hello,
	
	Difficult to answer. My guess:
	
	Distance 1.05157 is related to your lattice constant (and maybe you set it
	e.g. in eV instead of Ry when typing into w2web).
	
	Maybe the problem is also related to space group and inequivalent
	positions, I am not sure.
	
	You should probably attach 'struct' file. There was a discussion few days
	ago that the users should provide more information about their problems.
	Even if Prof. Blaha and few other experts are able to answer almost every
	question with minimum information included other guys (like me) may need
	some more. And then Prof. Blaha don't have to answer almost every single
	question himself :).
	
	What is the material ? How many atoms you have in the primitive cell ? -
	if its like 2 or 4 it would be very easy to find out where the distance
	of 1.05157 comes from.
	
	Regards,
	
	Lukasz
	
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