[Wien] where can i find the energy to eliminate semicore states
Michael Frotscher
frotscher at chemie.uni-hamburg.de
Fri Oct 17 11:31:46 CEST 2003
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Dear Dr. Blaha,
> ->>> E( 0)= -3.4675 E(BOTTOM)= -3.770 E(TOP)= -3.165 ->>>Ti 3s
> ->>> E( 1)= -1.7250 E(BOTTOM)= -2.180 E(TOP)= -1.270 ->>>Ti 3p
> ->>> E( 0)= -0.7800 E(BOTTOM)= -0.910 E(TOP)= -200.000 ->>> C 2s
(those were the lines that you marked)
> --->>> So the Ti 3s orbitals are around -3.4 Ry,
> 3p -1.65
> C 2s -0.15
I guess I now understand how WIEN treats core, semicore and valence states and of
course it is my decision which states to treat as which. With those values you stated,
I understand that setting the cutoff-energy to -1.0 Ry will include Carbon 2s-states
which therefore are included into the valence shell. But I don't really know how you
extracted the values you stated above from the scf-file, as I can't find them there.
Sincerely,
- --
Michael Frotscher
Institute of Inorganic and Applied Chemistry
University of Hamburg, Germany
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