[Wien] NOT A Bug report: find mistale with space group 141 - I41/amd
Jorissen Kevin
Kevin.Jorissen at ua.ac.be
Wed Sep 24 10:27:47 CEST 2003
Hello Dong Yuhui,
This is not a bug report, it's an input-problem-report. You're not the
first one who meets this 'problem' - in fact, if you search the mailing
list archives (the old ones) for 'anatase' you will find an e-mail by
Peter Blaha where he gives the correct struct-file for anatase.
The input is, indeed, a little tricky.
Here's the struct I used some time ago :
anatase
B LATTICE,NONEQUIV. ATOMS 2141_I41/amd
MODE OF CALC=RELA unit=bohr
7.135609 7.135609 17.925949 90.000000 90.000000 90.000000
ATOM -1: X=0.00000000 Y=0.25000000 Z=0.87500000
MULT= 2 ISPLIT=-2
-1: X=0.00000000 Y=0.75000000 Z=0.12500000
Ti1 NPT= 781 R0=0.00005000 RMT= 2.0000 Z: 22.0
LOCAL ROT MATRIX: 0.7071068-0.7071068 0.0000000
0.7071068 0.7071068 0.0000000
0.0000000 0.0000000 1.0000000
ATOM -2: X=0.00000000 Y=0.25000000 Z=0.66541830
MULT= 4 ISPLIT= 8
-2: X=0.00000000 Y=0.75000000 Z=0.33458170
-2: X=0.00000000 Y=0.75000000 Z=0.91541830
-2: X=0.50000000 Y=0.75000000 Z=0.58458170
O 1 NPT= 781 R0=0.00010000 RMT= 1.6000 Z: 8.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
16 NUMBER OF SYMMETRY OPERATIONS
Good luck,
Kevin.
-----Oorspronkelijk bericht-----
Van: Dong YuHui [mailto:dongyh at mail.ihep.ac.cn]
Verzonden: maandag 22 september 2003 17:05
Aan: Peter Blaha
CC: wien at zeus.theochem.tuwien.ac.at
Onderwerp: [Wien] Bug report: find mistale with space group 141 -
I41/amd
Dear Peter Blaha,
During the calculation of the TiO2 anatase phase, I input the space
group 141 - I41/amd, the program generatet the structure file as
TiO2-ana.struct, which is not consistent with the .cif file from ICSD
(TiO2-1.cif) and also the data from International Tables for
Crystallography. The diatance between Ti and O is too samll and the
calculation can not go on.
TiO2-ana.struct
B LATTICE,NONEQUIV.ATOMS: 2141_I41/amd
MODE OF CALC=RELA unit=ang
7.160553 7.160553 18.022325 90.000000 90.000000 90.000000 ATOM -1:
X=0.00000000 Y=0.00000000 Z=0.00000000
MULT= 4 ISPLIT= 8
ATOM -1:X= 0.25000000 Y=0.75000000 Z=0.25000000
ATOM -1:X= 0.00000000 Y=0.50000000 Z=0.00000000
ATOM -1:X= 0.25000000 Y=0.25000000 Z=0.75000000
Ti NPT= 781 R0=0.00005000 RMT= 2.0000 Z: 22.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
ATOM 2: X=0.00000000 Y=0.00000000 Z=0.28010000
MULT= 8 ISPLIT= 8
ATOM 2:X= 0.00000000 Y=0.00000000 Z=0.71990000
ATOM 2:X= 0.25000000 Y=0.75000000 Z=0.53010000
ATOM 2:X= 0.25000000 Y=0.75000000 Z=0.96990000
ATOM 2:X= 0.00000000 Y=0.50000000 Z=0.28010000
ATOM 2:X= 0.00000000 Y=0.50000000 Z=0.71990000
ATOM 2:X= 0.25000000 Y=0.25000000 Z=0.03010000
ATOM 2:X= 0.25000000 Y=0.25000000 Z=0.46990000
O NPT= 781 R0=0.00010000 RMT= 2.0000 Z: 8.0
The positions of Ti should be (0, 0, 0), (0, 1/2, 1/4), (1/2, 1/2, 1/2),
and (1/2, 0, 3/4) according to the International Tables of
Crystallography. Also the positions of O are not consistent with the
tables.
Regards,
Yu-Hui Dong
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