[Wien] Vacancy problem with Wien2k
Daniel Kmiec
kmiec at ap.univie.ac.at
Mon Mar 1 10:35:54 CET 2004
Dear Wien2k users,
I am quit new user of Wien2k, I tried to find answer for my question
in usersguide an mailing list but without luck.
Since some time I'm trying to calcute a surface system with a vacancy.
(for good display please use fixed font width)
This shows, how one layer looks like?
It is bcc 110 surface
O - vacancy
* - atom
top view of the surface
O ----------- * ----------- * ----------- O
| | | |
| * | * | * |
| | | |
* ----------- * ----------- * ----------- *
| | | |
| * | * | * |
| | | |
* ----------- * ----------- * ----------- *
| | | |
| * | * | * |
| | | |
O ----------- * ----------- * ----------- O
I have 5 such layers defined
vacum
surface .................
substrate -----------------
substrate -----------------
substrate -----------------
surface .................
vacum
The vacancy is only on surface, the substrate contains all atoms.
Now comes my question, when I'm not wrong in this case I should have 18
atoms per layer(or 17 + vacancy on the surface). This gives the total
number of atoms 88 + 2 vacancies. The symetry group I have in this case
is Pmmm and I have 23 inequivalent atoms.
Maybe this is a silly question but in "case.outputs" file I found line
which says that the number of atom is 352 (also 4 times bigger).
After the list of all 88 atoms with positions comes section:
DETERMINATION OF POINTGROUP FOR ALL POSITIONS
and there i see lines like this
...
Fe : 16 Atoms, Index 337 to 352
number of atoms: 352
...
I would like to know what is Wien2k doing here? It tries to generate all
possible positions of atoms, and then reduce the total number to only
inequivalent ones ? I hope it is calculating _only_ the cell with 88 atoms.
Best regards
Daniel Kmiec
--
____________________________________________________
Daniel Kmiec
Institut für Materialphysik
Strudlhofgasse 4 Tel : +43 1 4277 51310
1090 Wien, Austria Fax : +43 1 4277 9513
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