[Wien] Problems of WIEN2k in different systems
Jorissen Kevin
Kevin.Jorissen at ua.ac.be
Thu Oct 6 18:14:24 CEST 2005
Hi there,
1. If all the input is identical, then one of the installations is probably corrupted. Try to reproduce the examples in the WIEN UG or compare with other reliable data. Or find out in which program the two versions start to differ. Compile without optimization : does that change anything?
2. I don't really know how lstart chooses its TRIAL energies ... But let's look at the energies at the end of its scf cycle (for each atom, its last block in the case.outputst file) : are these reasonable?
good luck,
Kevin.
Kevin Jorissen
new contact address !!
Kevin Jorissen
University of Washington
Dept. of Physics
Box 351560
Seattle, WA-98195-1560
U.S.A.
phone +1 206 543 3904
fax +1 206 685 0635
e-mail kevin.jorissen at ua.ac.be
web page http://fraangelico.phys.washington.edu/~jorissen
________________________________
Van: wien-bounces at zeus.theochem.tuwien.ac.at namens kongshi
Verzonden: do 6-10-2005 5:13
Aan: wien at zeus.theochem.tuwien.ac.at
Onderwerp: [Wien] Problems of WIEN2k in different systems
Dear users:
I have some question of using WIEN2k recently.
1) It has same input file but the output is far different.
one is SUSE Linux 9.3, Intel ifort 9.0 MKL 8.0
:FER : F E R M I - ENERGY(TETRAH.M.)= 0.69978
the other is IBM P650 AIX 5.2 xlf ESSL
:FER : F E R M I - ENERGY(TETRAH.M.)= 0.95858
2) in my outputst file ( Pr )
ORBITAL OCCUPATION TRIAL ENERGIES
1S 1.000 -8.7025000E+02
1S 1.000 -8.7025000E+02
2S 1.000 -2.1756250E+02
2S 1.000 -2.1756250E+02
2P* 1.000 -2.1756250E+02
2P* 1.000 -2.1756250E+02
2P 2.000 -2.1756250E+02
2P 2.000 -2.1756250E+02
3S 1.000 -9.6694444E+01
3S 1.000 -9.6694444E+01
3P* 1.000 -9.6694444E+01
3P* 1.000 -9.6694444E+01
3P 2.000 -9.6694444E+01
3P 2.000 -9.6694444E+01
3D* 2.000 -9.6694444E+01
3D* 2.000 -9.6694444E+01
3D 3.000 -9.6694444E+01
3D 3.000 -9.6694444E+01
4S 1.000 -5.4390625E+01
4S 1.000 -5.4390625E+01
4P* 1.000 -5.4390625E+01
4P* 1.000 -5.4390625E+01
4P 2.000 -5.4390625E+01
4P 2.000 -5.4390625E+01
4D* 2.000 -5.4390625E+01
4D* 2.000 -5.4390625E+01
4D 3.000 -5.4390625E+01
4D 3.000 -5.4390625E+01
5S 1.000 -3.4810000E+01
5S 1.000 -3.4810000E+01
5P* 1.000 -3.4810000E+01
5P* 1.000 -3.4810000E+01
5P 2.000 -3.4810000E+01
5P 2.000 -3.4810000E+01
4F* 2.000 -5.4390625E+01 N
4F* 0.000 -5.4390625E+01 N
4F 0.000 -5.4390625E+01 N
4F 0.000 -5.4390625E+01 N
5D* 1.000 -3.4810000E+01 N
5D* 0.000 -3.4810000E+01 N
6S 1.000 -2.4173611E+01 N
6S 1.000 -2.4173611E+01 N
The energy of 4D is equal to 4F, which is correct? And how to solve if it's wrong?
Thank you ahead.
Best wishes,
-------------- next part --------------
A non-text attachment was scrubbed...
Name: not available
Type: application/ms-tnef
Size: 17047 bytes
Desc: not available
Url : http://zeus.theochem.tuwien.ac.at/pipermail/wien/attachments/20051006/36a04715/attachment.bin
More information about the Wien
mailing list