[Wien] Set of hard axis

[yasuharu_shiraishi at fujifilm.co.jp]

Dear Wien-users,

  I have a question how I can set hard axis of supercell.

  When I calculate FePt of unit cell, hard axis set as (1. 1. 0).
  If I calculate FePt of supercell,
  I wonder that I should set hard axis as (1. 1. 0.) or (2. 1. 0).
  Which is correct?

  Best regards.

  Coordinate of FePt is as follows.
  Fe (0.0 0.0 0.0)
  Pt (0.5 0.5 0.5)

  Coordinate of FePt of supercell is as follows
  Fe1 (0.0 0.0 0.0)
  Fe2 (0.0 0.5 0.0)
  Pt1 (0.5 0.25 0.5)
  Pt2 (0.5 0.25 0.5)