[Wien] Asking for set up case.inst
Khuong P. Ong
ongpk at ihpc.a-star.edu.sg
Tue Sep 27 11:17:03 CEST 2005
Dear Wien2k users,
Recently I have read the lecture note by Dr. Madsen and Dr. Novak
"calculate the effective U in APW methods".
There are something is unclear for me a bit. We really need your help.
The question is about how to set up NiO.inst for (4.5 up spin, 3 down
spin) calculation (everthing is clear for calculation with (4.5,4) ).
In (4.5,3) case, Ni has 7.5 3d electrons meanwhile the total number of
Ni valance electrons is 10, Ni- 3d8_ 4s2. Is it correct that we have to set
up the last 2.5 electron for Ni 4s? If it is so the following file is set up
Ni (Ni 1, is considered as impurity)
Ar 3 5
3, 2,2.0 P
3, 2,2.0 P
3,-3,2.5 P
3,-3,1.0 P ===> total 7.5 electron for Ni_ 3d
4,-1,1.25 N =====> max is 1?
4,-1,1.25 N =====> max is 1?
But I'm so afraid that I'm wrong. Or I understand wrongly about case.inst?
The User guide page 72-73, table 6.6 show that the max occupation for kappa
= -1 is 2. But here we split them into spin up and spin down therefore the
max occupation is 1 for each spin up/down. Am I correct?
- If not, please advice me on this.
- If it is true, could you help me to set up the NiO.inst file for the
calculation of (4.5 spin up ,3 spin down).
The same question is for Fe2O3 (the article Europhys. Letters. 69, 777
(2005)). Fe3+ has five 3d electrons. We don't know how to set up the
case.inst for both calculations: (3 spin up, 2.5 spin down) and (3 spin
up,1.5 spin down).
The Wien2k suggested the electronic configuration for case.inst with
3d6_4s2 (total 8 valance electrons). If we set up 5.5 or 4.5 electrons for
Fe_3d and how about the last 2.5 and 3.5 electron?
Please help me to clarify this puzzle. I deeply thank for your help.
Best regards,
Khuong
-------------- next part --------------
An HTML attachment was scrubbed...
URL: http://zeus.theochem.tuwien.ac.at/pipermail/wien/attachments/20050927/a8b38643/attachment.html
More information about the Wien
mailing list