[Wien] Case.inst and..

NAJMEH SOLTANI naj23s at yahoo.com
Wed Oct 25 14:29:53 CEST 2006


Dear wien users,
  I'm working with wien-O6 on a suse 10 in a pentium 4 pc.
  I'm working on AFM calculation for LaCrO3 in orthorombic with "Pnma" space group.I have 4 positions for Cr but, because LaCrO3 HAs G-type Magnetic order so I decided to break the symetry by labeling Cr in two different Cr,that each of them have two positions.then I had to set the lattice type "P".this is case.struct file:
   
  LaCrO3                                                                         
P   LATTICE,NONEQUIV.ATOMS:  5                                                 
MODE OF CALC=RELA unit=ang                                                     
 10.366818 14.679856 10.440120 90.000000 90.000000 90.000000                   
ATOM  -1: X=0.01675000 Y=0.25000000 Z=0.99625000
          MULT= 4          ISPLIT= 8
      -1: X=0.98325000 Y=0.75000000 Z=0.00375000
      -1: X=0.51675000 Y=0.25000000 Z=0.50375000
      -1: X=0.48325000 Y=0.75000000 Z=0.49625000
La1        NPT=  781  R0=0.00010000 RMT=    2.6000   Z: 57.0                   
LOCAL ROT MATRIX:    1.0000000 0.0000000 0.0000000
                     0.0000000 1.0000000 0.0000000
                     0.0000000 0.0000000 1.0000000
ATOM  -2: X=0.50000000 Y=0.50000000 Z=0.00000000
          MULT= 2          ISPLIT= 8
      -2: X=0.00000000 Y=0.00000000 Z=0.50000000
Cr1        NPT=  781  R0=0.00010000 RMT=    1.8000   Z: 24.0                   
LOCAL ROT MATRIX:    1.0000000 0.0000000 0.0000000
                     0.0000000 1.0000000 0.0000000
                     0.0000000 0.0000000 1.0000000
ATOM  -3: X=0.50000000 Y=0.00000000 Z=0.00000000
          MULT= 2          ISPLIT= 8
      -3: X=0.00000000 Y=0.50000000 Z=0.50000000
Cr2        NPT=  781  R0=0.00010000 RMT=    1.8000   Z:  8.0                   
LOCAL ROT MATRIX:    1.0000000 0.0000000 0.0000000
                     0.0000000 1.0000000 0.0000000
                     0.0000000 0.0000000 1.0000000
ATOM  -4: X=0.49358000 Y=0.25000000 Z=0.06466000
          MULT= 4          ISPLIT= 8
      -4: X=0.50642000 Y=0.75000000 Z=0.93534000
      -4: X=0.99358000 Y=0.25000000 Z=0.43534000
      -4: X=0.00642000 Y=0.75000000 Z=0.56466000
O 1        NPT=  781  R0=0.00050000 RMT=    1.6000   Z:  8.0                   
LOCAL ROT MATRIX:    1.0000000 0.0000000 0.0000000
                     0.0000000 1.0000000 0.0000000
                     0.0000000 0.0000000 1.0000000
ATOM  -5: X=0.22825000 Y=0.53503000 Z=0.22855000
          MULT= 8          ISPLIT= 8
      -5: X=0.77175000 Y=0.46497000 Z=0.77145000
      -5: X=0.72825000 Y=0.53503000 Z=0.27145000
      -5: X=0.27175000 Y=0.46497000 Z=0.72855000
      -5: X=0.27175000 Y=0.03503000 Z=0.72855000
      -5: X=0.72825000 Y=0.96497000 Z=0.27145000
      -5: X=0.77175000 Y=0.03503000 Z=0.77145000
      -5: X=0.22825000 Y=0.96497000 Z=0.22855000
O 2        NPT=  781  R0=0.00050000 RMT=    1.6000   Z:  8.0                   
LOCAL ROT MATRIX:    1.0000000 0.0000000 0.0000000
                     0.0000000 1.0000000 0.0000000
                     0.0000000 0.0000000 1.0000000
   4      NUMBER OF SYMMETRY OPERATIONS
-1 0 0 0.0000000
 0-1 0 0.0000000
 0 0-1 0.0000000
       1
 1 0 0 0.0000000
 0 1 0 0.0000000
 0 0 1 0.0000000
       2
-1 0 0 0.5000000
 0 1 0 0.5000000
 0 0 1 0.5000000
       3
 1 0 0 0.5000000
 0-1 0 0.5000000
 0 0-1 0.5000000
       4

  After that In initialize -calculation, in edit inst key I found this error," LaCrO3-inst not consistent wiyh z  edit Lacro3.inst and rerun lstart afterwards or change z in structgen."I 'm afraid wheather structgen does match the spacegroup or not?
  Please tell me what should I do.should I build cae.supergroup?If yes How?
  at the end this is my case.inst file I flliped spin in Cr2:
   
  La 1       
Xe 2  
5, 2,1.0  N
5, 2,0.0  N
6,-1,1.0  N
6,-1,1.0  N
Cr 1       
Ar 3  
3, 2,2.0  N
3, 2,2.0  N
3,-3,1.0  N
3,-3,0.0  N
4,-1,1.0  N
4,-1,0.0  N
Cr 2       
Ar 3  
3, 2,2.0  N
3, 2,2.0  N
3,-3,0.0  N -->spin flipped
3,-3,1.0  N -->spin flipped
4,-1,1.0  N
4,-1,0.0  N
O 1       
He 3  
2,-1,1.0  N
2,-1,1.0  N
2, 1,1.0  N
2, 1,1.0  N
2,-2,2.0  N
2,-2,0.0  N
O 2       
He 3  
2,-1,1.0  N
2,-1,1.0  N
2, 1,1.0  N
2, 1,1.0  N
2,-2,2.0  N
2,-2,0.0  N
****     End of Input
****     End of Input
according to page 72 UG,what does it mean that each s=+1 or s=-1 again split in two up and down states?Please tell me a source to Learn these relativistic Quantum Numbers.
  Best Regards,
  Najmeh
    

 			
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