[Wien] Re : Supercell problem of Al2O3
swati chaudhury
swati at rcais.res.in
Tue Aug 14 12:10:52 CEST 2007
Hi,
Thaks for the help. my problem is to generate Al2O3 supercell with vacuum slab in Wien2k.Basic inputs are given below for rhombohedral settings:
Cell parameters: 4.7626 4.7626 13.0032(ang) ; 90.000 90.00 90.00
Space group: 167 R-3c
Positions:
Al:0.3519208 0.3519208 0.3519208
0.8519208 0.8519208 0.8519208
0.1480792 0.1480792 0.1480792
0.6480792 0.6480792 0.6480792
O: 0.9437520 0.5562480 0.2500000
0.5562480 0.2500000 0.9437520
0.2500000 0.9437520 0.5562480
0.0562480 0.4437520 0.7500000
0.4437520 0.7500000 0.0562480
0.7500000 0.0562480 0.4437520
Thanks in advance.
Swati
"B. Yanchitsky" <yan at im.imag.kiev.ua> wrote:
Swati,
Could you provide once more Al and O positions for small cell,
lattice parameters,
and type (size) of supercell you are needed for?
Regards,
Bogdan Yanchitsky
Institute of Magnetism
Vernadsky Blvd., 36-b
03142 Kiev
UKRAINE
Tel. (+380-44) 444 34 20
Fax. (+380-44) 444 10 20
swati chaudhury wrote:
> Hi Michael and all wien users,
>
> Thanks for your suggestion.
> I have tried to generate Al2O3 supercell in Wien by following your
> suggestion. But yet,I have not got proper result.
> The structure files are attached.
> (1)File a.struct : Using Wyckoffpositions (4 Al & 6 O) but without
> adding transformation : lattice type selected
> :H
> Derived space group:193(P 63/mcm)and not the required 167R3cH
>
> (2) File a2.struct : Wycoff position with added transformation:
> (2/3,1/3,1/3)+ -Al
> (1/3,2/3,2/3)+ -O
> Lattice type selected : H
> Derived space group :1 P1
>
> (3)File A_latest.struct : Putting all 30 positions with added
> transformation :
> Lattice selected :P
> Derived space group : 15 (C 2/c)
> In no process my required space group is derived, ie 167 R-3c:H
> What can I do now? Please help me.
> Swati
>
> */Michael Fischer /* wrote:
>
> Hello,
>
> sorry, I was not aware that you cannot select the space group in
> hexagonal setting in structgen - as I said, I do not have much
> experience with rhombohedral and hexagonal cells in WIEN2k.
>
> I think you should do as follows: Choose H lattice type and enter the
> atoms separately. You have to enter 4 aluminium and 6 oxygen positions.
> The other ones should be generated by the lattice type. In order to
> find out which positions you need to enter, I suggest you use "WYCKPOS"
> of www.cryst.ehu.es. There, you enter space group 167 and look at the
> coordinates given for Wyckoff positions 12c (Al) and 18e (O). For x or
> z, you substitute the coordinate you have calculated.
> E.g. for Al at the position (0 0 0.35), i.e. z=0.35, you need to enter
> the four positions:
> 0 0 0.35
> 0 0 0.15
> 0 0 0.85
> 0 0 0.65
> Alternatively, select P lattice type and enter all 12 and 18 atoms
> respectively (more tedious). In addition to the above, you need to
> apply the transformations for all four Al and six O-positions.
> (2/3,1/3,1/3) +
> (1/3,2/3,2/3) +
>
> The cause why your second try did not work is easily explained: If you
> enter only two atoms and do not choose the correct space group,
> structgen does not know how to generate the symmetry-equivalent atoms.
> So you end up with a cell that has way too few atoms.
>
> Greetings
> Michael
>
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