[Wien] lcore problem
Amin Babazadeh
babazade at gmail.com
Sat Jul 21 08:03:43 CEST 2007
Dear users
I have a problem with running Baco3 case. My structure is
Baco3
P LATTICE,NONEQUIV.ATOMS:
462_Pmcn
MODE OF CALC=RELA
unit=ang
10.040119 16.826128 12.150944 90.000000 90.000000 90.000000
ATOM -1: X=0.25000000 Y=0.41631000 Z=0.75462000
MULT= 4 ISPLIT= 8
-1: X=0.75000000 Y=0.58369000 Z=0.24538000
-1: X=0.25000000 Y=0.08369000 Z=0.25462000
-1: X=0.75000000 Y=0.91631000 Z=0.74538000
Ba1 NPT= 781 R0= 0.00001000 RMT= 2.5000 Z: 56.0
LOCAL ROT MATRIX: 0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
ATOM -2: X= 0.25000000 Y=0.75630000 Z=0.91970000
MULT= 4 ISPLIT= 8
-2: X=0.75000000 Y=0.24370000 Z=0.08030000
-2: X=0.25000000 Y=0.74370000 Z=0.41970000
-2: X=0.75000000 Y=0.25630000 Z= 0.58030000
C 2 NPT= 781 R0=0.00010000 RMT= 1.2100 Z: 6.0
LOCAL ROT MATRIX: 0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
ATOM -3: X=0.25000000 Y=0.90100000 Z=0.91150000
MULT= 4 ISPLIT= 8
-3: X=0.75000000 Y=0.09900000 Z=0.08850000
-3: X=0.25000000 Y=0.59900000 Z=0.41150000
-3: X=0.75000000 Y=0.40100000 Z=0.58850000
O 3 NPT= 781 R0=0.00010000 RMT= 1.2100 Z: 8.0
LOCAL ROT MATRIX: 0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
ATOM -4: X=0.45960000 Y=0.68410000 Z=0.91940000
MULT= 8 ISPLIT= 8
-4: X=0.54040000 Y=0.31590000 Z=0.08060000
-4: X=0.45960000 Y=0.81590000 Z=0.41940000
-4: X=0.54040000 Y=0.18410000 Z=0.58060000
-4: X=0.95960000 Y=0.18410000 Z=0.58060000
-4: X=0.04040000 Y=0.81590000 Z=0.41940000
-4: X=0.95960000 Y=0.31590000 Z=0.08060000
-4: X=0.04040000 Y=0.68410000 Z=0.91940000
O 4 NPT= 781 R0=0.00010000 RMT= 1.2100 Z: 8.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
8 NUMBER OF SYMMETRY OPERATIONS
-1 0 0 0.00000000
0-1 0 0.00000000
0 0-1 0.00000000
1
1 0 0 0.00000000
0 1 0 0.00000000
0 0 1 0.00000000
2
-1 0 0 0.50000000
0-1 0 0.50000000
0 0 1 0.50000000
3
-1 0 0 0.00000000
0 1 0 0.50000000
0 0-1 0.50000000
4
-1 0 0 0.50000000
0 1 0 0.00000000
0 0 1 0.00000000
5
1 0 0 0.50000000
0-1 0 0.00000000
0 0-1 0.00000000
6
1 0 0 0.00000000
0-1 0 0.50000000
0 0 1 0.50000000
7
1 0 0 0.50000000
0 1 0 0.50000000
0 0-1 0.50000000
8
and it was running for only one cycle and in cycle 2 this error was occur
lcore.error
'CORE' - NSTOP= 210 positive eigenvalue for 1S Atom: 0 Ba1
'CORE' - Try to apply a potential shift in case.inc
as the error file said i use shift in potential with 5 and 3 but non of them
doesn't work. i put the case.inc file here for when i use shift with number
5.
14 5.00 NUMBER OF ORBITALS (EXCLUDING SPIN), SHIFT
1,-1,2 ( N,KAPPA,OCCUP)
2,-1,2 ( N,KAPPA,OCCUP)
2, 1,2 ( N,KAPPA,OCCUP)
2,-2,4 ( N,KAPPA,OCCUP)
3,-1,2 ( N,KAPPA,OCCUP)
3, 1,2 ( N,KAPPA,OCCUP)
3,-2,4 ( N,KAPPA,OCCUP)
3, 2,4 ( N,KAPPA,OCCUP)
3,-3,6 ( N,KAPPA,OCCUP)
4,-1,2 ( N,KAPPA,OCCUP)
4, 1,2 ( N,KAPPA,OCCUP)
4,-2,4 ( N,KAPPA,OCCUP)
4, 2,4 ( N,KAPPA,OCCUP)
4,-3,6 ( N,KAPPA,OCCUP)
1 0.00 NUMBER OF ORBITALS (EXCLUDING SPIN), SHIFT
1,-1,2 ( N,KAPPA,OCCUP)
1 0.00 NUMBER OF ORBITALS (EXCLUDING SPIN), SHIFT
1,-1,2 ( N,KAPPA,OCCUP)
1 0.00 NUMBER OF ORBITALS (EXCLUDING SPIN), SHIFT
1,-1,2 ( N,KAPPA,OCCUP)
would you please tell me what i should do for solving this problem?I know i
should shift in potential but i don't know how much. I try for 3,4 and 5 but
it doesn't work.
I will appreciate if some one help me.
Best the regards
--
AMIN
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