No subject
     
    
       
    Sat Jun 23 03:11:49 CEST 2007
    
    
  
>output, it can be seen you did a  non-spin-polarized calculation
(which <br>
>is wrong!), then both eigenvalues are doubly occupied, and you do
have <br>
>indeed 2s^2 2p^2, with the 2p eigenvalue equal to the Fermi energy.<br>
  <br>
>The FAQ clearly mentions that free atom calculations should be done
  <br>
>spin-polarized (you will see this will lower the energy compared to
your <br>
>non-spin-polarized :ENE).<br>
  <br>
>Stefaan<br>
  <br>
I have used for nonmagnetic isolated atom of C the spin polarized
calculations (in agreement with your recommendations and  FAQ) , </div>
  <div>and of course now I have magnetic moment of the nonmagnetic
atom!!! </div>
  <div> </div>
  <div>From band structure I can be seen that for spin up and for spin
down there is different energy flat levels for 2s and 2p, that is
properties of magnetic materials. </div>
  <div> </div>
  <div>Could you please say what do you think about this?</div>
  <div> </div>
  <div>Regards,</div>
  <div>Konstantin</div>
  <div> </div>
  <div> </div>
  <div> </div>
  <pre wrap="">
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