No subject
Sat Jun 23 03:11:49 CEST 2007
>output, it can be seen you did a non-spin-polarized calculation
(which <br>
>is wrong!), then both eigenvalues are doubly occupied, and you do
have <br>
>indeed 2s^2 2p^2, with the 2p eigenvalue equal to the Fermi energy.<br>
<br>
>The FAQ clearly mentions that free atom calculations should be done
<br>
>spin-polarized (you will see this will lower the energy compared to
your <br>
>non-spin-polarized :ENE).<br>
<br>
>Stefaan<br>
<br>
I have used for nonmagnetic isolated atom of C the spin polarized
calculations (in agreement with your recommendations and FAQ) , </div>
<div>and of course now I have magnetic moment of the nonmagnetic
atom!!! </div>
<div> </div>
<div>From band structure I can be seen that for spin up and for spin
down there is different energy flat levels for 2s and 2p, that is
properties of magnetic materials. </div>
<div> </div>
<div>Could you please say what do you think about this?</div>
<div> </div>
<div>Regards,</div>
<div>Konstantin</div>
<div> </div>
<div> </div>
<div> </div>
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