[Wien] Problem with DOS for Fe-Pd system
Maxim Rakitin
rms85 at physics.susu.ac.ru
Mon Sep 20 08:20:05 CEST 2010
Hi Robert,
Thank you for your support. The problem is solved now. I got fine graphs
for Ti and Fe DOS.
Best regards,
Maxim Rakitin
17.09.2010 17:56, Robert Laskowski пишет:
> Hi,
> if you did it with kgen, there is no reason not to trust the list, actual
> number in IBZ depends on symmetry operations you have.
>
> regards
>
> Robert
>
> On Friday 17 September 2010 12:18:58 Maxim Rakitin wrote:
>> Dear Robert,
>>
>> Thank you for such quick reply, I've increased the number of k-points to
>> 4x4x4, so there are 32 irreducible k-points now (with shift):
>> 1 1 1 1 8 2.0 -7.0
>> 1.5 64 k, div: ( 4 4 4)
>> 2 1 1 3 8 2.0
>> 3 1 1 5 8 2.0
>> 4 1 1 7 8 2.0
>> 5 1 3 1 8 2.0
>> 6 1 3 3 8 2.0
>> 7 1 3 5 8 2.0
>> 8 1 3 7 8 2.0
>> 9 1 5 1 8 2.0
>> 10 1 5 3 8 2.0
>> 11 1 5 5 8 2.0
>> 12 1 5 7 8 2.0
>> 13 1 7 1 8 2.0
>> 14 1 7 3 8 2.0
>> 15 1 7 5 8 2.0
>> 16 1 7 7 8 2.0
>> 17 3 1 1 8 2.0
>> 18 3 1 3 8 2.0
>> 19 3 1 5 8 2.0
>> 20 3 1 7 8 2.0
>> 21 3 3 1 8 2.0
>> 22 3 3 3 8 2.0
>> 23 3 3 5 8 2.0
>> 24 3 3 7 8 2.0
>> 25 3 5 1 8 2.0
>> 26 3 5 3 8 2.0
>> 27 3 5 5 8 2.0
>> 28 3 5 7 8 2.0
>> 29 3 7 1 8 2.0
>> 30 3 7 3 8 2.0
>> 31 3 7 5 8 2.0
>> 32 3 7 7 8 2.0
>> Could you please say whether they are correct and not double each other?
>>
>> Thank you for your help!
>> Maxim
>>
>> 17.09.2010 15:49, Robert Laskowski пишет:
>>> Hi,
>>> usually to get an elegant DOS more k-points are required then in the
>>> scf. Assuming your charge and potential are converged vs number of
>>> k-points. For dos doubling this number in each direction, usually is
>>> fine. And, yes, you can reuse your potential, you do not need to run the
>>> scf cycle, just run kgen, lapw1 and lapw2 -qtl.
>>>
>>> regards
>>>
>>> Robert
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