[Wien] QTL-B Error
محمد ارشد فرحان
arshadfarhan at hotmail.com
Wed Jul 4 12:24:53 CEST 2012
Dear stefaan,
i checked my case.in1c file, it does not have any other line for L=2.
. . .. . . 0.30 4 0 (GLOBAL E-PARAMETER WITH n OTHER CHOICES, global APW/LAPW) 1 0.30 0.000 CONT 1 1 -3.20 0.001 STOP 1 2 0.30 0.005 CONT 1 0 0.30 0.000 CONT 1 0.30 4 0 (GLOBAL E-PARAMETER WITH n OTHER CHOICES, global APW/LAPW) 1 0.30 0.000 CONT 1 1 -3.20 0.001 STOP 1 2 0.30 0.005 CONT 1 0 0.30 0.000 CONT 1. . .. . .
also the output file case.scf1up has it:
ATOMIC SPHERE DEPENDENT PARAMETERS FOR ATOM Mn3:e__0007: OVERALL ENERGY PARAMETER IS 0.3000 OVERALL BASIS SET ON ATOM IS LAPW:E1_0007: E( 1)= 0.3000 APW+lo:E1_0007: E( 1)= -3.2885 E(BOTTOM)= -3.322 E(TOP)= -3.255 LOCAL ORBITAL:E2_0007: E( 2)= 0.1875 E(BOTTOM)= -0.035 E(TOP)= 0.410 APW+lo:E0_0007: E( 0)= 0.3000 APW+lo
hope you can guide me further.Regards,M. Arshad Farhan
> Date: Wed, 4 Jul 2012 09:06:24 +0200
> From: Stefaan.Cottenier at UGent.be
> To: wien at zeus.theochem.tuwien.ac.at
> Subject: Re: [Wien] QTL-B Error
>
>
> Your E( 2)=0.1875 is a valence state, while the qtl-b error at -3.28 Ry
> is for a semicore state. There should be another line for atom 7 in your
> case.in1 with L=2, and with a strongly negative linearization energy.
> Change it to -3.2, and see whether the problem has gone.
>
> Stefaan
>
>
>
> On 4/07/2012 7:54, محمد ارشد فرحان wrote:
> > Dear Wien Users and Developers,
> >
> > i am encountered with QTL-B error. Althought UG has that covered in FAQ
> > , there is slight confusion i'm facing
> > the case.scf2 has
> >
> > Energy to separate low and high energystates: -0.38613
> >
> > :NOE : NUMBER OF ELECTRONS = 212.000
> >
> > :FER : F E R M I - ENERGY(TETRAH.M.)= 0.45195
> >
> > while the QTL-B error has the line: with *negative value of Energy*
> >
> > QTL-B VALUE .EQ. 30.11787 in *Band of energy -3.28095* ATOM= 7
> > L= 2
> >
> > Inspection of case.in1c gives me this line, where the default energy
> > parameter is positive as well as Fermi energy. it seems it has found the
> > E (Top) & E(bottom).
> >
> > :E2_0007: E( 2)= 0.1875 E(BOTTOM)= -0.035 E(TOP)= 0.410
> >
> > the case discussed in UG has all the energy values having same sign but
> > in this case, i'm confused.
> >
> > one more thing, the structure has reduced symmetry & this Atom 7 is Mn
> > as are Atom # 5, 6 & 8. but i only get problem for this Mn and not for
> > any other. the values in case.in1c are same for all the four Mn ions.
> >
> > please help me ,
> >
> > Regards,
> > M. Arshad Farhan
> >
> >
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> > Wien at zeus.theochem.tuwien.ac.at
> > http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
> >
>
>
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