[Wien] /lapw1para lapw1.def failed in run_lapw
Laurence Marks
L-marks at northwestern.edu
Thu Jul 19 19:28:02 CEST 2012
I do not see anything obvious, except that with an RKmax of 4 you may
not have enough memory. (You did not include the struct file.) I would
reduce it to 2.5 at least for the moment. For certain you should look
at the error files (cat *.error) for more information.
On Thu, Jul 19, 2012 at 12:22 PM, Kondaiah Samudrala
<konda.physics at gmail.com> wrote:
> Dear all,
>
> I am working on CHNO compounds, i modified the Rmax as 4 and GMax as 20,
> according to their NN distance. While running the run_lapw, i am facing
> same error like
>
> r2i0n3(1) 5.656u 54.699s 4:09.01 24.24% 0+0k 0+0io 0pf+0w
> r2i0n3(1) 4431.969u 90.002s 2:33:27.75 49.11% 0+0k 0+0io 0pf+0w
> r2i0n3(1) 4347.892u 105.587s 2:31:26.18 49.01% 0+0k 0+0io 0pf+0w
> r2i0n3(1) 4148.235u 103.650s 2:08:04.44 55.33% 0+0k 0+0io 0pf+0w
> r2i0n9(1) 5.452u 0.068s 5.62 98.10% 0+0k 0+0io 0pf+0w
> r2i0n9(1) 6.248u 0.104s 6.47 98.05% 0+0k 0+0io 0pf+0w
> ** LAPW1 crashed!
> 0.936u 195.784s 2:38:19.97 2.0% 0+0k 0+0io 174pf+0w
> error: command /home/gvacrc/Wien2k/lapw1para lapw1.def failed
>
>> stop error
>
>
> My .Struct file is in below
>
> ATOM 1 C ATOM 3 N
> RMT( 1)=1.24000 AND RMT( 3)=1.02000
> SUMS TO 2.26000 LT. NN-DIST= 2.64241
>
> ATOM 2 C ATOM 9 N
> RMT( 2)=1.24000 AND RMT( 9)=1.02000
> SUMS TO 2.26000 LT. NN-DIST= 2.49282
>
> ATOM 3 N ATOM 6 O
> RMT( 3)=1.02000 AND RMT( 6)=1.16000
> SUMS TO 2.18000 LT. NN-DIST= 2.36017
>
> ATOM 4 N ATOM 7 O
> RMT( 4)=1.02000 AND RMT( 7)=1.16000
> SUMS TO 2.18000 LT. NN-DIST= 2.34625
>
> ATOM 5 O ATOM 3 N
> RMT( 5)=1.16000 AND RMT( 3)=1.02000
> SUMS TO 2.18000 LT. NN-DIST= 2.36671
>
> ATOM 6 O ATOM 3 N
> RMT( 6)=1.16000 AND RMT( 3)=1.02000
> SUMS TO 2.18000 LT. NN-DIST= 2.36017
>
> ATOM 7 O ATOM 4 N
> RMT( 7)=1.16000 AND RMT( 4)=1.02000
> SUMS TO 2.18000 LT. NN-DIST= 2.34625
>
> ATOM 8 O ATOM 4 N
> RMT( 8)=1.16000 AND RMT( 4)=1.02000
> SUMS TO 2.18000 LT. NN-DIST= 2.34772
>
> ATOM 9 N ATOM 11 H
> RMT( 9)=1.02000 AND RMT( 11)=0.51000
> SUMS TO 1.53000 LT. NN-DIST= 1.64601
>
> ATOM 10 H ATOM 9 N
> RMT( 10)=0.51000 AND RMT( 9)=1.02000
> SUMS TO 1.53000 LT. NN-DIST= 1.66697
>
> ATOM 11 H ATOM 9 N
> RMT( 11)=0.51000 AND RMT( 9)=1.02000
> SUMS TO 1.53000 LT. NN-DIST= 1.64601
>
> ATOM 12 N ATOM 13 H
> RMT( 12)=1.02000 AND RMT( 13)=0.51000
> SUMS TO 1.53000 LT. NN-DIST= 1.58201
>
> ATOM 13 H ATOM 12 N
> RMT( 13)=0.51000 AND RMT( 12)=1.02000
> SUMS TO 1.53000 LT. NN-DIST= 1.58201
>
> ATOM 14 H ATOM 12 N
> RMT( 14)=0.51000 AND RMT( 12)=1.02000
> SUMS TO 1.53000 LT. NN-DIST= 1.58786
> NN ENDS
>
>
> I am new to wien2k..Pls help me in this
>
> with regards
> S.Appalakondaiah
>
--
Professor Laurence Marks
Department of Materials Science and Engineering
Northwestern University
www.numis.northwestern.edu 1-847-491-3996
"Research is to see what everybody else has seen, and to think what
nobody else has thought"
Albert Szent-Gyorgi
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