[Wien] case.inhf

[ali ghafari]

Dear Prof. Tran
Thank you very much for your replay.
But  Could you please explain to me how can I find the number of partially occupied band in case.scf?
I can not find any explanation in the UG.

Best Regards
Ali



________________________________
 From: "tran at theochem.tuwien.ac.at" <tran at theochem.tuwien.ac.at>
To: A Mailing list for WIEN2k users <wien at zeus.theochem.tuwien.ac.at> 
Sent: Wednesday, September 19, 2012 1:06 PM
Subject: Re: [Wien] case.inhf
 
Why not, but I think that it is not really more simple than just looking
at the number n_occ of (partially) occupied bands in case.scf and choosing
nband = n_occ + a few more bands. But remember that nband in case.inhf is
a parameter (similar to R*K_max) which has to be tested.

One last thing: the purpose of nband in case.in1 is not at all the same
as nband in case.inhf.

F. Tran

On Wed, 19 Sep 2012, ali ghafari wrote:

> Dear Prof. Blaha
> 
> For hybrid functionals case.inhf is necessary as discussed in the UG on pages 49 and 97. But the value of "nband' at case.inhf is confusing. on the page 97 of UG has mentioned "  .... nband should be at least equal to the number of (partially) occupied bands plus one". While at the line 5 of case.in1 the value of nband is automatically determined ( UG page 102) by "   nband = ne ∗ 2.0 + 5 " which is number of eigenvalues. Can we consider inband of case.inhf is equals: (eigenvalues -5)/2+1 which is extracted from case.in1?
>    
> 
> Best Regards
> Ali
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