[Wien] showing rhombohedral in hexagonal symmetry

[negin kamali]

Dear Wien2K Users,
I want to run the sm-element in hexagonal symmetry. Sm-element is a rhombohedral structure with 166(R-3m space group) and a=8.966A and alpha=23.13 and the atomic position are (0 0 0) (2/9 2/9 2/9) (7/9 7/9 7/9).
I know, In WIEN2K, when we want to run rhombohedral structure, we must to change the lattice constant to hexagonal which is in sm case a=b=3.621 and c=26.25 A (aphlfa=beta=90 and gamma=120), but i could not determine the positions in hexagonal axes.As you know in crystallography the R-3m space group has two sub-state first r-axes an second h-axes.
So, i want to know;

First: how the number of atoms are changed in this conversion (from rhombohedral to hexagonal symmetry)?  (it means, is it necessary to change number of atom when i want to convert a rhombohedral symmetry to hexagonal) Second: What are the atomic positions in h-axes?
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