[Wien] XPS is there a shift of fermi energy from core-hole? Can I estimate it?
David Olmsted
olmsted at berkeley.edu
Mon Apr 13 18:04:17 CEST 2015
Dear Peter and all list members,
[Peter, thanks again for the response below.]
I am modeling XPS binding energy using a one-half core-hole, offset by
background charge.
I am looking at the Al-2p states in the Al-P-O-H system, and looking at
shifts in the
XPS energy between hydrated and non-hydrated structures. This is for
comparison with experimental work.
Is there a shift in the Fermi energy because of the missing 1/2 electron?
(I believe Laurence Marks made a general mention of worrying about Fermi
energy shifts when doing XPS in this mailing list.) Since I have a finite
sized computational cell, it seems like reducing the number of electrons
should reduce the Fermi energy a bit, compared to a larger cell. Is this is
so, is there some way I can estimate it, either just to see if it is
significant, or perhaps even to correct for it?
Apparently I cannot compare the Fermi energy of different runs, each with
one-half of a core-hole but different numbers of atoms, because of the issue
of the zero of energy that Peter Blaha points out below.
Thanks,
David
David Olmsted
Assistant Research Engineer
Materials Science and Engineering
210 Hearst Memorial Mining Building
University of California
Berkeley, CA 94720-1760
-----Original Message-----
From: wien-bounces at zeus.theochem.tuwien.ac.at
[mailto:wien-bounces at zeus.theochem.tuwien.ac.at] On Behalf Of Peter Blaha
Sent: Friday, April 10, 2015 1:24 PM
To: A Mailing list for WIEN2k users
Subject: Re: [Wien] Which fermi energy for XPS?
No, I don't think so.
Every calculation uses its own Energy-zero (the average of the
Coulomb-potential in the interstitial region is set to zero), so clearly one
must use EF and E-2p from the same (half-core hole) calculation.
Eventually, you can check the k-mesh, as with a small k-mesh, EF could vary
a bit.
(I hope you have used "comparable k-meshes". This means the mesh for the
2x2x1 supercell should be by by a factor of two smaller in x,y than for the
primitive cell
(eg. 2x2x2 vs 4x4x2)
Am 10.04.2015 um 19:33 schrieb David Olmsted:
> I am modeling XPS binding energy using a half core-hole, offset by
> background charge. As I understand the method that has been explained
> here recently, one computes the binding energy as the energy of the
> state from case.scfc minus the Fermi energy from ':FER' in case.scf.
> Should the Fermi energy be for the configuration with the half
> core-hole, or a configuration without the core-hole? As explained
> below, from my results it looks as if it should be the same configuration,
but without the core hole.
>
> Some details:
> Version 14.2
> I am computing the differences in the XPS binding energy for Al-2p for
> cyrstals in the Al-P-O-H system to see how the binding energy changes
> between hydrated and non-hydrated configurations. This is for
> comparison with experimental results. (The actual material is
> amorphous, but I am hoping the effects of on the spectra will be at
> least qualitatively
> similar.)
>
> The simplest structure is AlPO4, berlinite. I have run two
> configurations, the primitive cell with 18 atoms, including 3 Al
> atoms, and a 2x2x1 supercell. In each case I have made one Al unique,
> then added one-half core-hole in case.inc and offset it with -0.5
background charge in case.inm.
> For simplicity I will show the results just for the triplet state.
> Lines are from case.scf and case.scfc.
>
> -------- 2x2x1 supercell, no core-hole
> :LABEL4: using the command: run_lapw -ec 0.00001 -p <skip>
> :FER : F E R M I - ENERGY(TETRAH.M.)= 0.0547409802
> :NEC01: NUCLEAR AND ELECTRONIC CHARGE 720.00000 720.00112
> :NEC02: NUCLEAR AND ELECTRONIC CHARGE 720.00000 720.00000
> :NEC03: NUCLEAR AND ELECTRONIC CHARGE 720.00000 720.00000
>
> -------- primitive cell, no core-hole
> :LABEL4: using the command: run_lapw -ec 0.00001 -p -NI <skip>
> :FER : F E R M I - ENERGY(TETRAH.M.)= 0.0564539224
> :NEC01: NUCLEAR AND ELECTRONIC CHARGE 180.00000 180.00073
> :NEC02: NUCLEAR AND ELECTRONIC CHARGE 180.00000 180.00000
> :NEC03: NUCLEAR AND ELECTRONIC CHARGE 180.00000 180.00000
>
> -------- 2x2x1 supercell, half core-hole
> :LABEL4: using the command: run_lapw -ec 0.00001 -p <skip>
> :WARN : CHARGED CELL with -0.500
> :FER : F E R M I - ENERGY(TETRAH.M.)= 0.0609755546
> :NEC01: NUCLEAR AND ELECTRONIC CHARGE 719.50000 719.50115
> :NEC02: NUCLEAR AND ELECTRONIC CHARGE 719.50000 719.50000
> :NEC03: NUCLEAR AND ELECTRONIC CHARGE 719.50000 719.50000
> <case.scfc>
> :2P 001: 2P -5.274530454 Ry
>
> ------- primitive cell, half core-hole
> :LABEL4: using the command: run_lapw -ec 0.00001 -p -NI
> :WARN : CHARGED CELL with -0.500
> :FER : F E R M I - ENERGY(TETRAH.M.)= 0.0944258517
> :NEC01: NUCLEAR AND ELECTRONIC CHARGE 179.50000 179.50067
> :NEC02: NUCLEAR AND ELECTRONIC CHARGE 179.50000 179.50000
> :NEC03: NUCLEAR AND ELECTRONIC CHARGE 179.50000 179.50000
> <case.scfc>
> :2P 001: 2P -5.268297265 Ry
>
> --------------
>
> The energy of the state differs by 6 mRy (85 meV) between the
> supercell and the primitive cell, making me hopeful that the supercell
> is reasonably converged as to size. The Fermi energy, though differs
> by 40 mRy (540 meV), so probably the supercell is not converged with
> respect to size for the Fermi energy. In the limit of a large
> supercell, it would seem that the Fermi energy should converge to the
> Fermi energy for the configuration without the core hole. So it seems
> to me that I should use the Fermi energy from the configuration
> without the core-hole and compute the binding energy as -5.2745 - 0.0547 =
-5.329 Ry. Is this correct?
>
> Thanks,
> David
>
> David Olmsted
> Assistant Research Engineer
> Materials Science and Engineering
> 210 Hearst Memorial Mining Building
> University of California
> Berkeley, CA 94720-1760
>
>
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--
-----------------------------------------
Peter Blaha
Inst. Materials Chemistry, TU Vienna
Getreidemarkt 9, A-1060 Vienna, Austria
Tel: +43-1-5880115671
Fax: +43-1-5880115698
email: pblaha at theochem.tuwien.ac.at
-----------------------------------------
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