[Wien] Spin part of the magnetic susceptibility

[pieper]

There have been several comments on this.

I can only guess at what exactly you want to calculate, but to me it 
seems that calculating a (zero-field) spin-resolved DOS would be a good 
start. Then you shift the spin-up and spin-down parts rigidly by mu_B*B 
by hand, and count how many mu_B you get per Tesla field.

If you want/need anything more elaborate you will have to provide more 
information on what kind of measurement in what kind of ferromagnetic 
metal or semiconductor you actually are interested in (and/or read 
Ashcroft & Mermin).


---
Dr. Martin Pieper
Karl-Franzens University
Institute of Physics
Universitätsplatz 5
A-8010 Graz
Austria
Tel.: +43-(0)316-380-8564


Am 21.07.2017 13:33, schrieb Wien2k User:
> Dear Wien2k Users;I am still waiting for an answer from Prof P.Blaha
> or Wien2k users
> 
> 2017-07-20 2:03 GMT+02:00 Wien2k User <wien2k.user at gmail.com>:
> 
>> dear wien2k users;
>> 
>> How to calculate the spin part of the magnetic susceptibility for a
>> ferromagnetic metal since the magnetic moment is different from
>> zero.
> _______________________________________________
> Wien mailing list
> Wien at zeus.theochem.tuwien.ac.at
> http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
> SEARCH the MAILING-LIST at:
> http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html