[Wien] Querry in a resultant structure
delamora
delamora at unam.mx
Sat Oct 28 15:01:16 CEST 2017
Is the AFMIII structure or not?
**** I do not understand this question
NB: What's mysterious is this AFM structure that the space group is monoclinic and the lattice parameters are orthorhombic.
**** My answer fits in this question; you have an orthorhombic cell, but it has atoms inside that break this symmetry, just as the example that I gave you, now the new symmetry is reduced.
Imagine a 2D square with atoms at
a,a
-a,a
a,-a
-a,-a
The symmetry is still square
Now if you associate, due to magnetic ordering, that is you put two atoms up and two down
Up; a,a -a,-a
Dn; -a,a a,-a
Then the structure is no longer square, it does not have 90 degrees rotations
________________________________
De: Wien <wien-bounces at zeus.theochem.tuwien.ac.at> en nombre de Abderrahmane Reggad <jazairdz at gmail.com>
Enviado: sábado, 28 de octubre de 2017 06:22 a. m.
Para: wien at zeus.theochem.tuwien.ac.at
Asunto: Re: [Wien] Querry in a resultant structure
Thanks Delamora for your answer and this is not what i am looking for and I am sorry that I couldn't communicate what I want.
My problem is as follows:
1- I am considering this non magnetic structure (orthorhombic )
* the non-magnetic structure is in this link
https://ibb.co/nt2nFm
* The struct file is:
NiS-MnP
P LATTICE,NONEQUIV.ATOMS: 2 62_Pnma
MODE OF CALC=RELA unit=ang
10.056514 6.692230 10.722761 90.000000 90.000000 90.000000
ATOM -1: X=0.00500000 Y=0.25000000 Z=0.20000000
MULT= 4 ISPLIT= 8
-1: X=0.99500000 Y=0.75000000 Z=0.80000000
-1: X=0.50500000 Y=0.25000000 Z=0.30000000
-1: X=0.49500000 Y=0.75000000 Z=0.70000000
Ni NPT= 781 R0=0.00005000 RMT= 2.08 Z:
28.0
LOCAL ROT MATRIX: 0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
ATOM -2: X=0.20000000 Y=0.25000000 Z=0.57000000
MULT= 4 ISPLIT= 8
-2: X=0.80000000 Y=0.75000000 Z=0.43000000
-2: X=0.70000000 Y=0.25000000 Z=0.93000000
-2: X=0.30000000 Y=0.75000000 Z=0.07000000
S NPT= 781 R0=0.00010000 RMT= 1.70 Z:
16.0
LOCAL ROT MATRIX: 0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
8 NUMBER OF SYMMETRY OPERATIONS
2- I want to construct the AFM structure of type III as in the following link
https://ibb.co/mqySFm
* I have used the supercell 1x1x1 P to make the four Ni atoms independent
* I have put the atoms (X=0.00500000 Y=0.25000000 Z=0.20000000) and (X=0.99500000 Y=0.75000000 Z=0.80000000) to UP
and the atoms (X=0.50500000 Y=0.25000000 Z=0.30000000) and (X=0.49500000 Y=0.75000000 Z=0.70000000) to DOWN
* I have used the sgroup
- I get the following AFM structure
NiS-MnP-afmIII
P LATTICE,NONEQUIV.ATOMS: 4
11_P21/m
MODE OF CALC=RELA
unit=bohr
10.998349 10.005529 6.864228 90.000000 90.000000
90.000000
ATOM -1: X=0.25021227 Y=0.99991424 Z=0.25000000
MULT= 2 ISPLIT= 8
-1: X=0.74978773 Y=0.00008576 Z=0.75000000
Ni1 NPT= 781 R0=0.00005000 RMT= 2.21 Z:
28.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
ATOM -2: X=0.75024661 Y=0.50012576 Z=0.75000000
MULT= 2 ISPLIT= 8
-2: X=0.24975339 Y=0.49987424 Z=0.25000000
Ni2 NPT= 781 R0=0.00005000 RMT= 2.21 Z:
28.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
ATOM -3: X=0.08986359 Y=0.75012482 Z=0.75000000
MULT= 2 ISPLIT= 8
-3: X=0.91013641 Y=0.24987518 Z=0.25000000
S 1 NPT= 781 R0=0.00010000 RMT= 1.81 Z:
16.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
ATOM -4: X=0.41013993 Y=0.25012471 Z=0.75000000
MULT= 2 ISPLIT= 8
-4: X=0.58986007 Y=0.74987529 Z=0.25000000
S 2 NPT= 781 R0=0.00010000 RMT= 1.81 Z:
16.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
4 NUMBER OF SYMMETRY OPERATIONS
My question is:
Is the AFMIII structure or not?
NB: What's mysterious is this AFM structure that the space group is monoclinic and the lattice parameters are orthorhombic.
Best regards
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