[Wien] Help me to solve #194 SG perovskites structure in AFM phase calculation problem
Peter Blaha
pblaha at theochem.tuwien.ac.at
Thu Aug 23 09:30:50 CEST 2018
From the files you sent, I never get Cm space group.
Anyway, if it is antiferromagnetic, it has only TWO Fe sites, one with
spin-up and one with dn.
So I used your struct file, but the 4 Fe atoms should probably not be
splitted into 1-4, but into two positions, each with multiplicity 2,
such that you get the desired udud spin-pattern.
sgroup gives then P63mc.
PS: You have to distinguish between a hexagonal bravais lattice
(aac,90,90,120) and a hexagonal space group. If you have a hexagonal
lattice, but put atoms in in an arbitrary way, it can easily even go to
P1. So the lattice is still hexagonal, but the SG does not belong to a
hexagonal SG, since the required symm.ops of a hex.SG are gone.
On 08/20/2018 02:54 PM, Enamul Haque wrote:
> Dear Wien2k Users and Experts,
>
>
> We already got sufficient help from Dr. Gavin in this case but we are
> not convinced from the space group point of view.
>
> With the original CIF file (attached), we want to check the ground state
> energy of the AFM case of "Cs3Fe2Cl9" (conventional standard and
> symmetrized taken from MP).
>
> The original structure crystallizes in hexagonal space group (194) with
> one Fe atom having multiplicity 4.
>
> So to do AFM calculations, we need four Fe atoms (udud configuration is
> reported as a stable structure in AFM case).
>
> We adopted two different ways to make four equivalent Fe atoms (to make
> udud AFM configuration) and in both the ways our space group adopts
> different geometry (SG) which does not fall within the hexagonal family.
>
> Original SG:
>
> H LATTICE,NONEQUIV.ATOMS: 5 194 P63/mmc
> MODE OF CALC=RELA unit=bohr
> 14.141194 14.141194 34.315650 90.000000 90.000000120.000000
> ATOM 1: X=0.66666733 Y=0.33333267 Z=0.41670700
>
>
> Labeling all Fe (1-4) in the file we get from cif2struct from
> conventional standard cif file:
>
> blebleble
> CXZ LATTICE,NONEQUIV.ATOMS: *22 8 Cm*
> MODE OF CALC=RELA unit=bohr
> 24.493266 42.160217 14.141194 90.000000 90.000000125.517869
> ATOM 1: X=0.26213500 Y=0.92880100 Z=0.00000000
>
> From the supercell approach (from /the symmetrized/ cif file after
> rounding off for two positions of Cl, ending with 50 and 800):
>
>
> /1. initialize (it should be in 194 SG)/
> /2. x supercell (1x1x1 with no shift)/
> /3. cp case_super.struct case.struct/
> /4. open in w2web and split one Fe and save it and it will redirect you
> again on w2web/
> /5. hit edit structure option and again click on second Fe to split and
> split all four Fe atoms/
> /6. again click on edit structure and put 1-4 on all four Fe atoms (in
> the second column) and remove original Fe atom (you see now five Fe
> atoms four that you have split and one will still on original position.
> So delete the original one)./
>
> It gave us (attached case.struct)
>
> H LATTICE,NONEQUIV.ATOMS: 16 *156 P3m1*
> MODE OF CALC=RELA unit=bohr
> 14.141194 14.141194 34.315650 90.000000 90.000000120.000000
>
>
> Now the issue we are facing is:
> The pristine structure is having SG 194 and after converting
> multiplicity of Fe atom to single atomic positions by two different
> approaches, we are getting two different SGs which do not fall within
> the hexagonal family.
>
>
> So, Could someone from the expert list please advice us how to do AFM
> calculations of this kind cases and which SG should be appropriate.It
> will be a great help.
>
>
>
>
>
> Best regards.
> Enamul Haque
> Mawlana Bhashani Science and Technology University
> Tangail, Bangladesh.
> Email: enamul at mailaps.org <mailto:enamul at mailaps.org>
> Cell: +8801831911133
>
>
>
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--
P.Blaha
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Peter BLAHA, Inst.f. Materials Chemistry, TU Vienna, A-1060 Vienna
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Email: blaha at theochem.tuwien.ac.at WIEN2k: http://www.wien2k.at
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