[Wien] Help on Core hole calculations
delamora
delamora at unam.mx
Fri May 17 14:38:45 CEST 2019
Estimado Israel,
You make long questions, and people do not read them
What about this cell
R LATTICE,NONEQUIV.ATOMS: 3 161_R3c
9.519303 9.519303 26.005203 90.000000 90.000000120.000000
ATOM -1: X=0.14500000 Y=0.14500000 Z=0.14500000
Fe1 NPT= 781 R0=0.00005000 RMT= 1.97 Z: 26.000
ATOM -2: X=0.05500001 Y=0.75000000 Z=0.44500000
O NPT= 781 R0=0.00010000 RMT= 1.69 Z: 8.000
ATOM -3: X=0.35500000 Y=0.35500000 Z=0.35500000
Fe2 NPT= 781 R0=0.00005000 RMT= 1.97 Z: 26.000
which you can even run with "runafm" (but without Hubbard U) with
-1 0 0 0
0 -1 0 0
0 0 -1 0
Saludos
Pablo
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