[Wien] Error in initialization step for Si example
Peter Blaha
pblaha at theochem.tuwien.ac.at
Fri Nov 1 07:37:01 CET 2019
The struct file has a fixed format and the atomic positions must be
listed in a correct way.
When you edit the struct file with an editor,always use "overwriting",
but do not shift digits to the left (positions of the second atom) or right.
Start over again.
Am 01.11.2019 um 02:51 schrieb Eesha Andharia:
> Dear Developers,
> I have always been able to successfully do the initialization step.
> However, I get the following error message while doing initialization
> and it stops working.
> /How should I proceed?/
> / next is symmetry
> > symmetry (20:44:26) forrtl: severe (24): end-of-file during
> read, unit 20, file /scrfs/storage/esandhar/home/Wein2k/new/Si/Si.struct
> Image PC Routine Line Source
> libifcoremt.so.5 00007F0ED388C572 for__io_return Unknown Unknown
> libifcoremt.so.5 00007F0ED38CC27D for_read_seq_fmt Unknown Unknown
> symmetry 000000000042FA84 latsym_.A 67 latsym.f
> symmetry 000000000040ADDE MAIN__.A 51
> symmetry.f
> symmetry 000000000040119E Unknown Unknown Unknown
> libc-2.12.so <http://libc-2.12.so> 00007F0ED1BB1D20
> __libc_start_main Unknown Unknown
> symmetry 00000000004010A9 Unknown Unknown Unknown
> 0.006u 0.010s 0:00.02 50.0% 0+0k 0+8io 0pf+0w
> error: command /scrfs/apps/WIEN2k/19.2el6/19.2/symmetry symmetry.def
> failed
> \n stop error \n/
>
> Also, here is my Si.struct file:
> Si
> F LATTICE,NONEQUIV.ATOMS: 1
> MODE OF CALC=RELA unit=ang
> 10.26000 10.26000 10.26000 90.00000 90.00000 90.00000
> ATOM 1: X=0.12500000 Y=0.12500000 Z=0.12500000
> MULT= 2 ISPLIT= 2
> 1: X=0.87500000 Y=0.87500000 Z=0.87500000
> Si1 NPT= 781 R0=0.00010000 RMT= 2.1000 Z: 14.0
> LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
> 0.0000000 1.0000000 0.0000000
> 0.0000000 0.0000000 1.0000000
> 48 NUMBER OF SYMMETRY OPERATIONS
> 1 0 0 0.00000000
> 0 1 0 0.00000000
> 0 0 1 0.00000000
> 1
> -1 0 0 0.75000000
> 0-1 0 0.25000000
> 0 0 1 0.50000000
> 2
> -1 0 0 0.25000000
> 0 1 0 0.50000000
> 0 0-1 0.75000000
> 3
> 1 0 0 0.50000000
> 0-1 0 0.75000000
> 0 0-1 0.25000000
> 4
> 0 0 1 0.00000000
> 1 0 0 0.00000000
> 0 1 0 0.00000000
> 5
> 0 0 1 0.50000000
> -1 0 0 0.75000000
> 0-1 0 0.25000000
> 6
> 0 0-1 0.75000000
> -1 0 0 0.25000000
> 0 1 0 0.50000000
> 7
> 0 0-1 0.25000000
> 1 0 0 0.50000000
> 0-1 0 0.75000000
>
> Awaiting your reply.
>
> Regards,
> Eesha
>
>
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--
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Peter BLAHA, Inst.f. Materials Chemistry, TU Vienna, A-1060 Vienna
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