[Wien] NMR chemical shift calculations

Peter Blaha pblaha at theochem.tuwien.ac.at
Mon Feb 17 11:38:17 CET 2020


Your system is metallic !!!

For metals you have to use the    -metal  switch

x_nmr -metal

In addition you should use a fermi smearing (TEMP with 4-6 mRy)  and you 
will need to check k-point convergence.

On 2/14/20 9:56 PM, Nader Ghassemi wrote:
> Dear WIEN2K experts,
> 
> I am trying to calculate the NMR chemical shift for Cu12Sb4S13.
> I am running wien2K on 4 cores PC with operating system Ubuntu 16-04, 
> Fortran compiler intel and math libraries mkl.
> I am using the spacegroup-217 structure.
> The  DOS and band structure calculation goes smoothly without any 
> errors. However, after setting up the chemical shift calculations, in 
> the final case.outputnmr_integ file for the chemical shift, I get * In 
> place of many of the calculated values in the results. Below is an 
> extract of the calculated chemical shifts.
> 
> :NMRTOT001  ATOM:     Cu1+   1  NMR(total/ppm) Sigma-ISO =********** 
>      Sigma_xx =**********   Sigma_yy =**********   Sigma_zz =**********
> :NMRASY001  ATOM:     Cu1+   1  NMR(total/ppm) ANISO (delta-sigma) = 
> -53300.41     ASYM (eta) = 0.000     SPAN =  53300.41     SKEW =-1.000
> 
> :NMRTOT001  ATOM:     Cu1+   1  NMR(total/ppm) Sigma-ISO =********** 
>      Sigma_xx =**********   Sigma_yy =**********   Sigma_zz =**********
> :NMRASY001  ATOM:     Cu1+   1  NMR(total/ppm) ANISO (delta-sigma) = 
> -53300.41     ASYM (eta) = 0.000     SPAN =  53300.41     SKEW =-1.000
> 
> :NMRTOT001  ATOM:     Cu1+   1  NMR(total/ppm) Sigma-ISO =********** 
>      Sigma_xx =**********   Sigma_yy =**********   Sigma_zz =**********
> :NMRASY001  ATOM:     Cu1+   1  NMR(total/ppm) ANISO (delta-sigma) = 
> -53300.41     ASYM (eta) = 0.000     SPAN =  53300.41     SKEW =-1.000
> 
> 
> 
> Note that I do not get any error message during the calculations, and 
> the resulting density of states looks quite similar to what is expected 
> from other publications. However, clearly there is a problem with the 
> NMR calculation. If there are any suggestions about this please let me 
> know. Since there is no explicit error I was not sure what to try. Note 
> that Cu12Sb4S13 has its Fermi surface inside one of the bands, making it 
> metallic, and in this calculation, I have only considered 1728 K points. 
> I realize that a denser grid is likely required for accuracy but it 
> appears that perhaps there is some more fundamental problem. Also, my 
> real interest is in comparing to substituted Cu12Sb4S13 materials which 
> are semiconducting, and I tried artificially placing Ef into the 
> semiconducting gap for this material, but with the same error. Also, I 
> did get a warning :
> $ x_nmr_lapw -mode in1 -p
> 
> EXECUTING:     /home/lab/Downloads/Wien2k/nmrc -case Cu12Sb4S13_test1 
> -mode in1 -nodes 8 -green -ovlpmax 0.4
> 
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.99 
> setting new lo energy:  0.30
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.96 
> setting new lo energy:  0.80
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.92 
> setting new lo energy:  1.30
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.87 
> setting new lo energy:  1.80
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.79 
> setting new lo energy:  2.30
> :WARNINIG  ATOM=   3  L= 0  HIGH OVERLAP between radial functions 0.70 
> setting new lo energy:  2.80
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.99 
> setting new lo energy:  0.30
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.98 
> setting new lo energy:  0.80
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.96 
> setting new lo energy:  1.30
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.93 
> setting new lo energy:  1.80
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.90 
> setting new lo energy:  2.30
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.86 
> setting new lo energy:  2.80
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.81 
> setting new lo energy:  3.30
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.75 
> setting new lo energy:  3.80
> :WARNINIG  ATOM=   4  L= 0  HIGH OVERLAP between radial functions 0.69 
> setting new lo energy:  4.30
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.99 
> setting new lo energy:  0.30
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.98 
> setting new lo energy:  0.80
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.96 
> setting new lo energy:  1.30
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.93 
> setting new lo energy:  1.80
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.90 
> setting new lo energy:  2.30
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.86 
> setting new lo energy:  2.80
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.81 
> setting new lo energy:  3.30
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.75 
> setting new lo energy:  3.80
> :WARNINIG  ATOM=   5  L= 0  HIGH OVERLAP between radial functions 0.69 
> setting new lo energy:  4.30
> 
> 
> NUMBER OF RADIAL FUNCTIONS IN case.in1_nmr
> ATOM     L=0     L=1     L=2     L=3
> 1       9       9       9       9
> 2       9       9       9       9
> 3      10       9      10       9
> 4      10       9       9
> 5      10       9       9
> 
> 
> 
> 
> but I have seen this in other calculations which ran to completion with 
> no apparent problems.
> 
> 
> I appreciate any help,
> 
> Thank you,
> Nader
> 
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-- 

                                       P.Blaha
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Peter BLAHA, Inst.f. Materials Chemistry, TU Vienna, A-1060 Vienna
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