<div dir="ltr">Than you so much its clear<br></div><div class="gmail_extra"><br><br><div class="gmail_quote">On Tue, Apr 30, 2013 at 1:27 PM, Rocquefelte <span dir="ltr"><<a href="mailto:xavier.rocquefelte@cnrs-imn.fr" target="_blank">xavier.rocquefelte@cnrs-imn.fr</a>></span> wrote:<br>
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<div>Don't forget that border atoms are
shared with other cells !<br>
Thus for Mg atoms you have:<br>
- 8 Mg at the corners - each shared between 8 cells -> 8/8 =1
Mg in 1 cell<br>
- 6 Mg at the center of the faces - each shared by 2 cells ->
6/2 = 3 Mg in 1 cell<br>
- 4 Mg inside the cell<br>
<br>
Thus you have 8/8 + 6/2 + 4 = 8 Mg atoms in one cell.<br>
<br>
Regards<br>
<br>
Xavier <br>
<br>
<br>
<br>
<br>
Le 4/30/2013 6:22 AM, Zaid a écrit :<br>
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<div dir="ltr">Respected Community<br>
<div dir="ltr"><br>
I have a little confusion in understanding the spinel
structure. I am attaching a perfect MgAl2O4 spinel structure.
Why this structure shows more than 8 Mg (Yellow in colour)
elements ? There should be 8 Mg, 16 Al and 32 O atoms that
adds up to give 56 atoms. I also see more no of atoms in
Xcrysden. <br>
<br>
Best wishes<br>
</div>
<div>Zaid<br>
</div>
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<br>
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