<div dir="ltr">Dear all,<div><br></div><div>I was trying to calculate the optical properties of Al(111) slab. For the bulk FCC Al, I can reproduce the dielectric functions and plasma frequency very precisely reported in literature before. However, I did find some difference between the slab dielectric functions and the corresponding bulk values. </div>
<div><br></div><div>Especially even though I used very thick slab, say 39MLs, in the low photo energy range (<1eV), the imaginary part is much larger than the bulk. I doubt this may be related to the band-folding and symmetry reduction in the direction normal to the surface. </div>
<div><br></div><div>Also, I found the plasma frequency of the slab is smaller than the bulk plasma frequency.</div><div><br></div><div>Mathematically, this behavior of the imaginary parts of the interband and intraband transitions contributions seems to be able to be understood from the f-sum rule. </div>
<div><br></div><div>1) However, physically it's hard to believe, because when the slab thickness is very thick for example the 39MLs used in my test calculation, the slab wavefunctions should be very very close to the bulk wavefunction except in the very thin slab/vacuum interface region. This should give us the dielectric functions for the slab which are very very close to the bulk values. This argument should be also true for the slab plasma frequency.</div>
<div><br></div><div>2) If the different values are because of the surface slab structure we used in the calculation, which indeed breaks the translational symmetry in the normal direction. Then the question is that in real experiment because the sample always is finite with the boundary surface, how can we get the dielectric information really for the ideal bulk rather than the slab similar as that mentioned above. Or in calculating dielectric function, when should we use bulk geometry? when should we use slab geometry?</div>
<div><br></div><div>Thanks a lot for any idea.</div><div><br></div><div>Wenmei</div><div><br></div><div><br></div><div><br></div><div><br></div><div><br></div><div><br></div></div>