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<p>Sorry for this question, it has been answered before; </p>
<p>--------- (2/22/2012)</p>
<p>So most likely mBJ + U gives the better solution, but probably the U should be smaller than in LDA+U, because mBJ already shifts the f-states a bit.<br>
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<p>--------<br>
</p>
<p>but I am still confused, in GW and DMFT calculations the Hubbard U is still a parameter, so; </p>
<p>Does the mBJ needs a not precisely known parameter?</p>
<p> Saludos</p>
<p> Pablo<br>
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<p>Dear P Blaha and F Tran,<br>
</p>
<p>I would like to ask if with the </p>
<p> modified Becke Johnson potential</p>
<p>one should use the Hubbard U?</p>
<p><br>
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<p> Saludos<br>
</p>
<p><br>
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<p> Pablo<br>
</p>
<p><br>
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