<div dir="ltr">Dear Fecher<div>Sorry I can not understand about which energy your are asking about. My intention was to see B effects on EFG.</div><div>Without B_ext</div><div><br></div><div>By the way with B_ext TOTAL ENERGY IN Ry = -89574.89351208</div></div><div class="gmail_extra"><br><div class="gmail_quote">On Wed, Sep 9, 2015 at 1:14 PM, Fecher, Gerhard <span dir="ltr"><<a href="mailto:fecher@uni-mainz.de" target="_blank">fecher@uni-mainz.de</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Did you check how much the energy is changed if you apply an external field of 8 T<br>
the Bohr magneton is approximately 58 x 10^-6 eV / T<br>
<br>
Ciao<br>
Gerhard<br>
<br>
DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:<br>
"I think the problem, to be quite honest with you,<br>
is that you have never actually known what the question is."<br>
<br>
====================================<br>
Dr. Gerhard H. Fecher<br>
Institut of Inorganic and Analytical Chemistry<br>
Johannes Gutenberg - University<br>
55099 Mainz<br>
and<br>
Max Planck Institute for Chemical Physics of Solids<br>
01187 Dresden<br>
________________________________________<br>
Von: <a href="mailto:wien-bounces@zeus.theochem.tuwien.ac.at">wien-bounces@zeus.theochem.tuwien.ac.at</a> [<a href="mailto:wien-bounces@zeus.theochem.tuwien.ac.at">wien-bounces@zeus.theochem.tuwien.ac.at</a>] im Auftrag von Muhammad Sajjad [<a href="mailto:sajjadpu@gmail.com">sajjadpu@gmail.com</a>]<br>
Gesendet: Montag, 7. September 2015 09:55<br>
An: A Mailing list for WIEN2k users<br>
Betreff: Re: [Wien] EFG dependence on magnetic field<br>
<span class=""><br>
Dear Gavin<br>
Bundle of thanks for such a helping reply. Are the case.inorb and case.indm files are ok now for B-ext applied at 32 degree angle with x-axis?<br>
<br>
<br>
================== case.inorb =====================<br>
3 2 0 nmod, natorb, ipr<br>
PRATT 1.0 BROYD/PRATT, mixing<br>
1 1 2 iatom nlorb, lorb<br>
<br>
2 1 2 iatom nlorb, lorb<br>
<br>
8. Bext 1. 0.62487 0. direction ============================================== ================== case.indm ===================== -9. Emin cutoff energy 2 number of atoms for which density matrix is calculated 1 1 2 index of 1st atom, number of L's, L1<br>
<br>
2 1 2 dtto for 2nd atom, repeat NATOM times<br>
<br>
0 0 r-index, (l,s)index ==============================================<br>
<br>
</span><span class="">On Sun, Sep 6, 2015 at 9:14 PM, Gavin Abo <<a href="mailto:gsabo@crimson.ua.edu">gsabo@crimson.ua.edu</a><mailto:<a href="mailto:gsabo@crimson.ua.edu">gsabo@crimson.ua.edu</a>>> wrote:<br>
<br>
Many thanks for your guidance. Actually my system has magnetic (2) and non-magnetic (3) species. As B_ext. means we are apply magnetic field on the whole system then why do we need to select natorb = 2 ?<br>
<br>
Bext is applied to the iatoms (i.e., in atomic spheres) that you specify in case.inorb. The program searches for file case.vorbup, if it finds it, Bext energy is add to Vxc in atomic spheres and in interstitial region [ <a href="http://www.wien2k.at/reg_user/textbooks/orbital_potentials.pdf" rel="noreferrer" target="_blank">http://www.wien2k.at/reg_user/textbooks/orbital_potentials.pdf</a> (section "4.1 LAPW0 package" on page 6)].<br>
<br>
Secondly could you please clarify to me about "adjusting the "direction of Bext in terms of lattice vectors" line in case.inorb. ". Any example please or guidance that how to make it.<br>
<br>
For example,<br>
<br>
y = x*tan(theta) = 1*tan(32 degrees) = 0.62487 [ <a href="https://en.wikipedia.org/wiki/Trigonometry" rel="noreferrer" target="_blank">https://en.wikipedia.org/wiki/Trigonometry</a> ]<br>
<br>
Consider a cubic lattice with the "direction of Bext in terms of lattice vectors" set to:<br>
<br>
1 0.62487 0<br>
<br>
Calculation of the angle between vector (1,0,0) and vector (1,0.62487,0) with octave:<br>
<br>
username@computername:~/wiendata/case$ octave<br>
octave:1> a=[1 0 0]<br>
a =<br>
1 0 0<br>
octave:2> b=[1 0.62487 0]<br>
b =<br>
1.00000 0.62487 0.00000<br>
octave:3> angle_rad=acos(dot(a,b)/(norm(a)*norm(b)))<br>
angle_rad = 0.55851<br>
octave:4> angle_deg=angle_rad*180/pi<br>
angle_deg = 32.000<br>
<br>
This gives an angle of 32 degrees with respect to the (100) axis.<br>
<br>
Reference: <a href="http://www.mathworks.com/matlabcentral/newsreader/view_thread/151925" rel="noreferrer" target="_blank">http://www.mathworks.com/matlabcentral/newsreader/view_thread/151925</a><br>
<br>
</span>[<a href="mailto:cid%3Apart1.02070908.02000808@crimson.ua.edu">cid:part1.02070908.02000808@crimson.ua.edu</a>]<br>
<br>
<br>
<br>
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KAUST, KSA.<br>
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<br></blockquote></div><br><br clear="all"><div><br></div>-- <br><div class="gmail_signature"><div dir="ltr"><div>Kind Regards</div><div>Muhammad Sajjad </div><div>Post Doctoral Fellow</div><div>KAUST, KSA.</div></div></div>
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