<div dir="ltr">Thank you very much and <span class="gmail-" id="gmail-result_box" lang="en"><span class="gmail-">as you said, we are still waiting for a confirmation from Prof. P. Blaha and Wien2k users.<br></span></span></div><div class="gmail_extra"><br><div class="gmail_quote">2017-09-30 21:53 GMT+02:00 Yundi Quan <span dir="ltr"><<a href="mailto:yquan@ucdavis.edu" target="_blank">yquan@ucdavis.edu</a>></span>:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir="ltr">Hi, <div><br>As I understand it, the susceptibility you obtain by shifting DOS is the Pauli susceptibility, i.e. itinerant electrons near the Fermi level. But I might be wrong.</div><div><br></div><div><br></div><div><br></div><div><br></div></div><div class="gmail_extra"><br><div class="gmail_quote"><span class="">On Sat, Sep 30, 2017 at 8:40 AM, karima Physique <span dir="ltr"><<a href="mailto:physique.karima@gmail.com" target="_blank">physique.karima@gmail.com</a>></span> wrote:<br></span><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><span class=""><div dir="ltr">Dear Prof. P. Blaha and Wien2k user;<div><br></div><div><br></div><div>Is the spin part of the magnetic susceptibility due to the contribution of delocalized electrons only?<br></div></div>
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