<div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div class="gmail_quote"><div dir="ltr" class="gmail_attr">Dear All, <br></div><div dir="ltr"><div dir="ltr"><div dir="ltr"><div dir="ltr"><div><div><br></div><div>I am doing calculations on a material Nd2PdSi3 which is of AlB2 hexagonal structure (space group P6/mmm) with lattice constants a=b= 4.103 ang and c = 4.204 ang. The positions of the atoms are as follows: R 1a site 0 0 0 and Pd and Si statistically distributed on the 2d site 1/3 2/3 1/2 with 25 % and 75% respectively. I started making the structure using R at 1a site and Si at 2d site, so I get one Nd atom and two Si atoms.</div><div><br></div><div><div>Title</div><div>H  LATTICE,NONEQUIV.ATOMS: 2 191_P6/mmm</div><div>MODE OF CALC=RELA unit=ang</div><div> 7.754116 7.754116 7.944223 90.000000 90.000000120.000000</div><div>ATOM -1: X=0.00000000 Y=0.00000000 Z=0.00000000</div><div>     MULT= 1     ISPLIT= 8</div><div>Nd     NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 60.000</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM  2: X=0.33333333 Y=0.66666667 Z=0.50000000</div><div>     MULT= 2     ISPLIT= 8</div><div>ATOM  2:X= 0.66666667 Y=0.33333333 Z=0.50000000</div><div>Si     NPT= 781 R0=0.00010000 RMT=  2.2200  Z: 14.000</div><div>LOCAL ROT MATRIX:  0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>  0   NUMBER OF SYMMETRY OPERATIONS</div><div>~                                                      </div><div>In order to make the ratio of Pd:Si as 1:3, I have doubled the structure along x axis using the super cell program, The structure is shown below:<br></div></div><div><div><div><br></div><div><div>Title</div><div>P  LATTICE,NONEQUIV. ATOMS 4</div><div>MODE OF CALC=RELA unit=ang</div><div> 15.508232 7.754116 7.944223 90.000000 90.000000120.000000</div><div>ATOM  1: X=0.00000000 Y=0.00000000 Z=0.00000000</div><div>     MULT= 1     ISPLIT= 8</div><div>Nd     NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 60.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM  2: X=0.50000000 Y=0.00000000 Z=0.00000000</div><div>     MULT= 1     ISPLIT= 8</div><div>Nd     NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 60.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM  3: X=0.16666666 Y=0.66666667 Z=0.50000000</div><div>     MULT= 2     ISPLIT= 8</div><div>ATOM  3: X=0.33333334 Y=0.33333333 Z=0.50000000</div><div>Si     NPT= 781 R0=0.00010000 RMT=  2.2200  Z: 14.0</div><div>LOCAL ROT MATRIX:  0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>ATOM  4: X=0.66666666 Y=0.66666667 Z=0.50000000</div><div>     MULT= 2     ISPLIT= 8</div><div>ATOM  4: X=0.83333334 Y=0.33333333 Z=0.50000000</div><div>Si     NPT= 781 R0=0.00010000 RMT=  2.2200  Z: 14.0</div><div>LOCAL ROT MATRIX:  0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>           0.0000000 0.0000000 0.0000000</div><div>  0   NUMBER OF SYMMETRY OPERATIONS</div></div><div><br></div><div><div>After this I splitted the 2nd atomic position of the 3rd Si atom and then changed the atom from Si to Pd and the Z value to 46 i.e, for Pd and then saved the structure. <br></div></div></div><div><br></div><div>When I initialized I got the following warning:</div><div><div>SUMS TO 4.44000 LT. NN-DIST= 4.47684</div><div> WARNING: Mult not equal. PLEASE CHECK outputnn-file</div><div> WARNING: ityp not equal. PLEASE CHECK outputnn-file</div><div> WARNING: ityp not equal. PLEASE CHECK outputnn-file</div></div><div><br></div><div>Then I accepted the structure given by x sgroup and I get the following struture</div><div><br></div><div><div>Title</div><div>P  LATTICE,NONEQUIV.ATOMS: 6 25 Pmm2</div><div>       RELA</div><div> 7.754116 7.944223 13.430523 90.000000 90.000000 90.000000</div><div>ATOM -1: X=0.00000000 Y=0.00000000 Z=0.00000000</div><div>     MULT= 1     ISPLIT= 8</div><div>Nd1    NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 60.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM -2: X=0.50000000 Y=0.00000000 Z=0.50000000</div><div>     MULT= 1     ISPLIT= 8</div><div>Nd2    NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 60.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM -3: X=0.49999999 Y=0.50000000 Z=0.83333334</div><div>     MULT= 1     ISPLIT= 8</div><div>Pd1    NPT= 781 R0=0.00001000 RMT=  2.5000  Z: 46.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM -4: X=0.00000000 Y=0.50000000 Z=0.33333334</div><div>     MULT= 1     ISPLIT= 8</div><div>Si1    NPT= 781 R0=0.00010000 RMT=  1.8900  Z: 14.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM -5: X=0.50000001 Y=0.50000000 Z=0.16666666</div><div>     MULT= 1     ISPLIT= 8</div><div>Si2    NPT= 781 R0=0.00010000 RMT=  1.8900  Z: 14.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>ATOM -6: X=0.00000000 Y=0.50000000 Z=0.66666666</div><div>     MULT= 1     ISPLIT= 8</div><div>Si3    NPT= 781 R0=0.00010000 RMT=  1.8900  Z: 14.0</div><div>LOCAL ROT MATRIX:  1.0000000 0.0000000 0.0000000</div><div>           0.0000000 1.0000000 0.0000000</div><div>           0.0000000 0.0000000 1.0000000</div><div>  4   NUMBER OF SYMMETRY OPERATIONS</div><div> 1 0 0 0.00000000</div><div>Now the question is my initial experimental structure was AlB2 hexagonal type but since I could not have Pd and Si distribution in this structure in 1:3 ratio I made a supercell and the structure which I have generated now is Pmm2 structure which is orthorhombic but has a distribution of Pd and Si in 1:3 ratio. Is it ok to perform calculations on this structure?    <br></div><div><br></div><div>Secondly, I want to perform Antiferromagnetic calculations with different magnetic configurations like A, C, G type and for that I have to further increase the supercell. That in itself will further change the symmetry. Can I use this structure and make a super cell to define the magnetic configuration for the Nd ion?    </div><div>Please suggest.</div><div><br></div><div>Sincerely,        </div></div></div></div><div dir="ltr" class="gmail-m_-3873913793653173719gmail_signature"><div dir="ltr"><div dir="ltr"><div dir="ltr" style="font-size:12.8px"><font color="#333333"><font face="tahoma, sans-serif">Anup Pradhan Sakhya (Ph.D.)</font></font></div><div dir="ltr" style="font-size:12.8px"><font color="#333333" face="tahoma, sans-serif">Visiting Post-Doctoral Fellow</font></div><div dir="ltr" style="font-size:12.8px"><font color="#333333" face="tahoma, sans-serif">DCMP&MS, TIFR, Mumbai</font></div></div></div></div></div></div></div></div></div></div></div></div></div></div></div></div></div>