[Wien] re : Supercells - what is the right procedure to create an
acceptable one?
George Amolo
amolo at schonlan.src.wits.ac.za
Tue Jun 15 13:12:51 CEST 2004
Dear Wien2k users,
I am a fairly new user of the Wien2k code trying out some calculations of
dopant impurities in a diamond lattice supercell. The users forum has been
of immense help to me. I have followed with interest suggestions of Steven
Homolya (21st - 23rd October 2004) on how to fix hand-made struct files
and hence modify them to supercells. The last email, 23rd October, has a
caution from Jorrisen Kevin about the CXZ-bug if one accepts all the
output from sgroup. Would someone out there kindly outline in simple terms
what should be done.
I have started out with (despite Stefan's caution to Yaron and Angelica of
18th Jul 2003 not to give a spacegroup but rather start from a
P-structfile. This is because that route had even more problems)
diamond
F LATTICE,NONEQUIV. ATOMS 1227_Fd-3m
MODE OF CALC=RELA unit=bohr
6.740660 6.740660 6.740660 90.000000 90.000000 90.000000
ATOM 1: X=0.12500000 Y=0.12500000 Z=0.12500000
MULT= 2 ISPLIT= 2
1: X=0.87500000 Y=0.87500000 Z=0.87500000
C C1 NPT= 781 R0=0.00010000 RMT= 1.4500 Z: 6.0
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
and went ahead to use the 'supercell' command online. Several warnings
appeared. I went ahead and accepted the suggested changes by updating them
to the case.struct file and then through the process of intialization of the
struct file which is now essentially that of a supercell. Note that a
nitrogen atoms was inserted into the supercell. The struct file before
running 'mini' is
Title
R 4 166 R-3m
RELA
9.532733 9.532733 23.350331 90.000000 90.000000120.000000
ATOM -1: X=0.31278464 Y=0.31278464 Z=0.81217227
MULT= 6 ISPLIT= 8
-1: X=0.81217227 Y=0.31278464 Z=0.31278464
-1: X=0.31278464 Y=0.81217227 Z=0.31278464
-1: X=0.68721536 Y=0.68721536 Z=0.18782773
-1: X=0.68721536 Y=0.18782773 Z=0.68721536
-1: X=0.18782773 Y=0.68721536 Z=0.68721536
C 1 NPT= 781 R0=.000100000 RMT= 1.45000 Z: 6.00000
LOCAL ROT MATRIX: 0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
ATOM -2: X=0.81302209 Y=0.81302209 Z=0.30880538
MULT= 6 ISPLIT= 8
-2: X=0.30880538 Y=0.81302209 Z=0.81302209
-2: X=0.81302209 Y=0.30880538 Z=0.81302209
-2: X=0.18697791 Y=0.18697791 Z=0.69119462
-2: X=0.18697791 Y=0.69119462 Z=0.18697791
-2: X=0.69119462 Y=0.18697791 Z=0.18697791
C 2 NPT= 781 R0=.000100000 RMT= 1.45000 Z: 6.00000
LOCAL ROT MATRIX: 0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
1.0000000 0.0000000 0.0000000
ATOM -3: X=0.31301112 Y=0.31301112 Z=0.31301112
MULT= 2 ISPLIT= 4
-3: X=0.68698888 Y=0.68698888 Z=0.68698888
N 1 NPT= 781 R0=.000100000 RMT= 1.45000 Z: 7.00000
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
ATOM -4: X=0.81511300 Y=0.81511300 Z=0.81511300
MULT= 2 ISPLIT= 4
-4: X=0.18488700 Y=0.18488700 Z=0.18488700
C 3 NPT= 781 R0=.000100000 RMT= 1.45000 Z: 6.00000
LOCAL ROT MATRIX: 1.0000000 0.0000000 0.0000000
0.0000000 1.0000000 0.0000000
0.0000000 0.0000000 1.0000000
12 NUMBER OF SYMMETRY OPERATIONS
1 0 00.00000000
0 1 00.00000000
0 0 10.00000000
1
0 0 10.00000000
1 0 00.00000000
0 1 00.00000000
2
0 1 00.00000000
0 0 10.00000000
1 0 00.00000000
3
0-1 00.00000000
-1 0 00.00000000
0 0-10.00000000
4
-1 0 00.00000000
0 0-10.00000000
0-1 00.00000000
5
0 0-10.00000000
0-1 00.00000000
-1 0 00.00000000
6
-1 0 00.00000000
0-1 00.00000000
0 0-10.00000000
7
0 0-10.00000000
-1 0 00.00000000
0-1 00.00000000
8
0-1 00.00000000
0 0-10.00000000
-1 0 00.00000000
9
0 1 00.00000000
1 0 00.00000000
0 0 10.00000000
10
1 0 00.00000000
0 0 10.00000000
0 1 00.00000000
11
0 0 10.00000000
0 1 00.00000000
1 0 00.00000000
12
I invoked min_lapw -j 'run_lapw -I -fc 1.0 -i 50' for a trial minimization
and run the following 'mini' error after more than an hour
'NN' - overlapping spheres
'NN' - RMT( 1)=1.45000 AND RMT( 2)=1.45000
'NN' - SUMS TO 2.90000 GT NNN-DIST= 2.89817
Please advice me on this rather long story. Thank you.
george Amolo
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