[Wien] AFM calculation
thomas.mazet
Thomas.Mazet at lcsm.uhp-nancy.fr
Fri Jan 14 16:06:24 CET 2005
Dear Sir,
About your second question concerning the non-zero magnetic moment on Bi
and O atoms (I have not verify the details of your input files) : it is
normal that in magnetic compounds (even in antiferromagnets) nominally
'diamagnetic' atoms possess a low magnetic moment : it is induced by
spin-dependent chemical bonds with the magnetic atoms (like iron). You can
think in terms of molecular fields : if the magnetic configuration of the
neighboring iron moments around Bi or O is such that it leads to a
non-zero molecular field at Bi or O (to be verified), a small magnetic
moment is expected on Bi ot O. These small magnetic moments on
nominally non-magnetic atoms are responsible for the hyperfine fields
at their nucleus you can measure using several experimental
techniques like RMN, Mössbauer ... There are
a lot of papers from the seventies, eighties and nineties describing
this spin-dependent chemical bond whose authors are Williams, Kubler,
Johansson, Brooks, Kanamori, Akai ....
I hope it helps you.
Regards,
Thomas
> Dear Peter Blaha , Stefaan Cottenier¡¯s and wien user:
> I am doing a AFM calculation. In according to the UG and the Stefaan
> Cottenier¡¯s suggestion, I construct the AFM case.struct. In my original
> case.struct, I split the positions of the Fe-atoms according to their spin.
> In the Fe position with MULT=2 has one atom with spin up and one with spin
> dn, I make one positions with MULT=1 out of it. Give these two different
> spin types a different label. Run now init_lapw, and accept all structure
> changes proposed by nn and sgroup. Moreover, I put the correct up and dn
> occupations for Fe in the final case.inst file before proceeding with
> lstart. Then I begin always to use a regular
> runsp_lapw. The result is : MAGNETIC MOMENTS OF MIXED CHARGE DENSITY
> :MMINT: MAGNETIC MOMENT IN INTERSTITIAL = 0.00000
> :MMI001: MAGNETIC MOMENT IN SPHERE 1 = -0.00256
> :MMI002: MAGNETIC MOMENT IN SPHERE 2 = 0.00255
> :MMI003: MAGNETIC MOMENT IN SPHERE 3 = 3.66726
> :MMI004: MAGNETIC MOMENT IN SPHERE 4 = -3.66725
> :MMI005: MAGNETIC MOMENT IN SPHERE 5 = 0.05963
> :MMI006: MAGNETIC MOMENT IN SPHERE 6 = -0.05963
> :MMTOT: TOTAL MAGNETIC MOMENT IN CELL = 0.00000
>
> The original-case.inst and the flip-case.inst as follow:
> Oringial-case.inst
> Bi
> Xe 7 5
> 4, 3,3.0 N
> 4, 3,3.0 N
> 4,-4,4.0 N
> 4,-4,4.0 N
> 5, 2,2.0 N
> 5, 2,2.0 N
> 5,-3,3.0 N
> 5,-3,3.0 N
> 6,-1,1.0 N
> 6,-1,1.0 N
> 6, 1,1.0 N
> 6, 1,1.0 N
> 6,-2,1.0 N
> 6,-2,0.0 N
> Bi
> Xe 7 5
> 4, 3,3.0 N
> 4, 3,3.0 N
> 4,-4,4.0 N
> 4,-4,4.0 N
> 5, 2,2.0 N
> 5, 2,2.0 N
> 5,-3,3.0 N
> 5,-3,3.0 N
> 6,-1,1.0 N
> 6,-1,1.0 N
> 6, 1,1.0 N
> 6, 1,1.0 N
> 6,-2,1.0 N
> 6,-2,0.0 N
> Fe
> Ar 3 5
> 3, 2,2.0 N
> 3, 2,2.0 N
> 3,-3,2.5 N
> 3,-3,0.0 N
> 4,-1,1.0 N
> 4,-1,0.5 N
> Fe
> Ar 3 5
> 3, 2,2.0 N
> 3, 2,2.0 N
> 3,-3,2.5 N
> 3,-3,0.0 N
> 4,-1,1.0 N
> 4,-1,0.5 N
> O
> He 3 5
> 2,-1,1.0 N
> 2,-1,1.0 N
> 2, 1,1.0 N
> 2, 1,1.0 N
> 2,-2,2.0 N
> 2,-2,0.0 N
> O
> He 3 5
> 2,-1,1.0 N
> 2,-1,1.0 N
> 2, 1,1.0 N
> 2, 1,1.0 N
> 2,-2,2.0 N
> 2,-2,0.0 N
> ****
> **** END of input (instgen_lapw)
>
> flip-case.inst
> Bi
> Xe 7 5
> 4, 3,3.0 N
> 4, 3,3.0 N
> 4,-4,4.0 N
> 4,-4,4.0 N
> 5, 2,2.0 N
> 5, 2,2.0 N
> 5,-3,3.0 N
> 5,-3,3.0 N
> 6,-1,1.0 N
> 6,-1,1.0 N
> 6, 1,1.0 N
> 6, 1,1.0 N
> 6,-2,0.5 N <=== equal occup for up/dn
> 6,-2,0.5 N <=== equal occup for up/dn
> Bi
> Xe 7 5
> 4, 3,3.0 N
> 4, 3,3.0 N
> 4,-4,4.0 N
> 4,-4,4.0 N
> 5, 2,2.0 N
> 5, 2,2.0 N
> 5,-3,3.0 N
> 5,-3,3.0 N
> 6,-1,1.0 N
> 6,-1,1.0 N
> 6, 1,1.0 N
> 6, 1,1.0 N
> 6,-2,0.5 N <=== equal occup for up/dn
> 6,-2,0.5 N <=== equal occup for up/dn
> Fe
> Ar 3 5
> 3, 2,2.0 N
> 3, 2,2.0 N
> 3,-3,2.5 N
> 3,-3,0.0 N
> 4,-1,1.0 N
> 4,-1,0.5 N
> Fe
> Ar 3 5
> 3, 2,2.0 N
> 3, 2,2.0 N
> 3,-3,0.0 N <=== spin flipped
> 3,-3,2.5 N <=== spin flipped
> 4,-1,0.5 N <=== spin flipped
> 4,-1,1.0 N <=== spin flipped
>
> O
> He 3 5
> 2,-1,1.0 N
> 2,-1,1.0 N
> 2, 1,1.0 N
> 2, 1,1.0 N
> 2,-2,1.0 N <=== equal occup for up/dn
> 2,-2,1.0 N <=== equal occup for up/dn
> O
> He 3 5
> 2,-1,1.0 N
> 2,-1,1.0 N
> 2, 1,1.0 N
> 2, 1,1.0 N
> 2,-2,1.0 N <=== equal occup for up/dn
> 2,-2,1.0 N <=== equal occup for up/dn
> ****
> **** END of input (instgen_lapw)
> I have two question:
> 1 Is it right for my claculational method?
> 2 I do no kmow why the MAGNETIC MOMENT of the Bi abd O atom is non-zero?
> Any help and suggestion is welcome!
>
>
> Yours Meng-Qiu Cai
>
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--
Thomas MAZET
Laboratoire de Chimie du Solide Minéral (UMR 7555)
Université Henri Poincaré-Nancy I
BP 239 54506 Vandoeuvre les Nancy Cedex
FRANCE
Tel.: +33-(0)3-83-68-46-77
Fax : +33-(0)3-83-68-46-11
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