[Wien] optical conductivity or electronic conductivity?

[shamik chakrabarti]

Dear Nazma,

                   Thank you very much for your reply. To further clarify my
doubt I am asking one more question. If we get one peak in the optical (i.e.
electronic) conductivity spectrum does it mean that at that frequency more
photons will be absorbed giving high value of its absorbtance and also high
value of electronic conductivity i.e. does it mean at that frequency the
material is electronically conducting (transparent) but optically opaque?...

Shamik Chakrabarti

2009/10/30 Nazma Ikram <nazmaikram at hotmail.com>

>
> The word optical here means that e m radiations in the frequency range
> corresponding to optical spectum are incident  on the semiconductor, causing
> transition of electrons (hence electronic) from the valence to conduction
> band.
> ------------------------------
> Date: Thu, 29 Oct 2009 10:26:29 +0530
> From: shamikphy at gmail.com
> To: wien at zeus.theochem.tuwien.ac.at
> Subject: [Wien] optical conductivity or electronic conductivity?
>
>
> Dear wien2k users,
>
>          By calculating  dielectric tensor we can calculate electronic
> conductivity. I have calculated dielectric tensor and from which I have also
> deduced electronic conductivity sigma by following the relation:
>
>      Im.epsilon=sigma/omega
>
> where sigma=electronic conductivity
> and omega=angular frequency of the EM wave (energy*2pi/h)
>
> Now In file case.absorpup (or dn) we can find the data for optical
> conductivity in unit 1/(ohm.cm). But when I plot optical and electronic
> conductivity separately I have found they are exactly the same. Then my
> question is
>
> Q: whether we find optical or electronic conductivity in the file
> case.absorpup?
>
> P.S. optical and electronic conductivity are not the same thing!...glass is
> electronically insulating but optically conducting (transparent) material.
>
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