[Wien] Hubbard U and mBJ
delamora
delamora at unam.mx
Fri May 1 23:14:59 CEST 2015
Sorry for this question, it has been answered before;
--------- (2/22/2012)
So most likely mBJ + U gives the better solution, but probably the U should be smaller than in LDA+U, because mBJ already shifts the f-states a bit.
--------
but I am still confused, in GW and DMFT calculations the Hubbard U is still a parameter, so;
Does the mBJ needs a not precisely known parameter?
Saludos
Pablo
________________________________
Dear P Blaha and F Tran,
I would like to ask if with the
modified Becke Johnson potential
one should use the Hubbard U?
Saludos
Pablo
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